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lilavasa [31]
3 years ago
8

How many more times is kinetic energy increased if velocity triples?

Physics
1 answer:
san4es73 [151]3 years ago
8 0
Nine times more (squared speed)
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A particle of mass M moves along a straight line with initial speed vi. A force of magnitude F pushes the particle a distance D
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Answer:

Explanation:

Initial kinetic energy of M = 1/2 M vi²

let final velocity be vf

v² = u² + 2a s

vf² =  vi² + 2 (F / M) x D

Kinetic energy

= 1/2 Mvf²

= 1/2 M ( vi² + 2 (F / M) x D

1/2 M vi² + FD

Ratio with initial value

1/2 M  vi² + FD) / 1/2 M  vi²

RK = 1 + FD / 2 M  vi²

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3 years ago
A horizontal line above the time axis of a speed vs. time graph means an object is ___.
miv72 [106K]
A horizontal line on a speed/time graph means a constant speed.
6 0
3 years ago
A car dropped from a height of 44 meters fall to a height of zero meters. How fast will the car be traveling as it hits the grou
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Vi=0m/s
Vf=?
A=9.81
D=44
T=not needed

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6 0
2 years ago
The formula K2S indicates that
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There are two atoms of potassium bonded to one atom of sulfur.
4 0
3 years ago
A woman walked 115 m. As she did so, her speed increased from 4.20 m/s to 5.00 m/s. How long did it take her to walk this distan
ASHA 777 [7]

Answer:

25 seconds

Explanation:

Assuming the woman is accelerating at a constant rate of a \;\;m/s^2 from the initial velocity, u=4.20 m/s, to the final velocity, v=5.00 m/s.

Let she takes t seconds to cover the distance, s=115 m.

As acceleration, a=\frac{v-u}{t}=\frac{5-4.2}{t}

\Rightarrow at=0.8\cdots(i)

Now, from the equation of motion

s=ut+\frac 12 at^2

\Rightarrow s=ut+\frac 12 at(t)

\Rightarrow 115=4.2t+\frac 12 \times 0.8 t [ from equation (i)]

\Rightarrow 115=(4.2+0.4)t

\Rightarrow t= 115/4.6 = 25 seconds.

Hence, she takes 25 seconds to walk the distance.

5 0
3 years ago
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