Question

A 61.5 KG student sits at a desk 1.2 5M away from a 70.0 KG student. What is the magnitude of the gravitational force between the two students?

Answer 1

mass of two students are

$m_1 = 61.5 kg$

$m_2 = 70 kg$

distance between them is given as

$r = 1.25 m$

now gravitational force between them is given as

$F = \frac{Gm_1m_2}{r^2}$

now plug in all values

$F = \frac{6.67\times 10^{-11} \times 61.5 \times 70}{1.25^2}$

$F = 1.84 \times 10^{-7} N$

so above is the force of gravitation between them