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KiRa [710]
3 years ago
7

A -kilogram car travels at a constant speed of 20. meters per second around a horizontal circular track. The diameter of the tra

ck is meters. The magnitude of the car's centripetal acceleration is:_______
Physics
1 answer:
Tatiana [17]3 years ago
4 0

Answer:

The centripetal acceleration of the car is 8\ m/s^2.

Explanation:

Let the mass of the car, m=10^3\ kg

Diameter of the circular path, d = 100 m

Speed of car, v = 20 m/s

Radius, r = 50 m

When an object moves in a circular path, the centripetal acceleration acts on it. It is given by :

a=\dfrac{v^2}{r}

a=\dfrac{(20\ m/s)^2}{50\ m}

a=8\ m/s^2

So, the centripetal acceleration of the car is 8\ m/s^2. Hence, this is the required solution.

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Just about everyone at one time or another has been burned by hot water or steam. This problem compares the heat input to your s
tatyana61 [14]

Answer:

Q_T=63313.5\ J

Explanation:

Given:

  • temperature of skin, T_s=34^{\circ}C
  • initial temperature of steam vapour, T_v=100^{\circ}C
  • latent heat of steam, L=2256\ J.g^{-1}
  • mass of steam, m=25\ g
  • specific heat of water, c=4190\ J.kg^{-1}.K^{-1}=4.19\ J.g^{-1}.K^{-1}
  • final temperature, T_f=34^{\circ}C

<em>Assuming that no heat is lost in the surrounding.</em>

<u>We know:</u>

Q=m.c.\Delta T

<u>Now the total heat given by the steam to form water at the given conditions:</u>

Q_T=Q_{Lv}+Q_w ..............................(1)

where:

Q_{Lv}= latent heat given out by vapour to form water of 100°C

Q_w= heat given by water of 100°C to come at 34°C.

putting respective values in eq. (1)

Q_T=m(L+c.\Delta T)

Q_T=25(2256+4.19\times 66)

Q_T=63313.5\ J

is the heat transferred to the skin.

4 0
3 years ago
Two balls have their centers 2.0 m apart. One ball has a mass of m1 = 7.9 kg. The other has a mass of m2 = 6.1 kg. What is the g
maks197457 [2]

Answer:

3.036×10⁻¹⁰ N

Explanation:

From newton's law of universal gravitation,

F = Gm1m2/r² .............................. Equation 1

Where F = Gravitational force between the balls, m1 = mass of the first ball, m2 = mass of the second ball, r = distance between their centers.

G = gravitational constant

Given: m1 = 7.9 kg, m2 = 6.1 kg, r = 2.0 m, G = 6.67×10⁻¹¹ Nm²/C²

Substituting into equation 1

F = 6.67×10⁻¹¹×7.9×6.1/2²

F = 321.427×10⁻¹¹/4

F = 30.36×10⁻¹¹

F = 3.036×10⁻¹⁰ N

Hence the force between the balls = 3.036×10⁻¹⁰ N

8 0
3 years ago
How do things rust? Is this chemical or mechanical weathering?
IrinaK [193]
I'll say that's mechanical weathering
6 0
3 years ago
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A manufacturer claims its cleanser works twice as fast as any other. Could test be performed to support the claim? Explain
lora16 [44]

Yes, a test could be performed to support the claim.

 

Hypothesis: The claim that a manufacturer’s cleanser works twice as fast as any other cleanser.

 

So, based from this hypothesis, we can perform the following tests:

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1.       Get two tiles and put the same amount of stain on them.

2.       Apply Cleanser A on the first tile and Cleanser B on the second tile.

3.       Apply the same amount of force in removing the stains on both tiles

4.       Record the amount of time it takes to remove the stains on each tile.

4 0
3 years ago
Which statement about the total velocity of a projectile launched at an angle less than 90° above a flat surface is true?
marissa [1.9K]

The correct answer is B the total velocity is equal at both landing and launch because before your about launch you have 0 velocity then when you have landed you also have 0 velocity. Hope This Helps

3 0
2 years ago
Read 2 more answers
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