Question

A -kilogram car travels at a constant speed of 20. meters per second around a horizontal circular track. The diameter of the track is meters. The magnitude of the car's centripetal acceleration is:_______

Answer 1

Answer:

The centripetal acceleration of the car is $8\ m/s^2$.

Explanation:

Let the mass of the car, $m=10^3\ kg$

Diameter of the circular path, d = 100 m

Speed of car, v = 20 m/s

Radius, r = 50 m

When an object moves in a circular path, the centripetal acceleration acts on it. It is given by :

$a=\dfrac{v^2}{r}$

$a=\dfrac{(20\ m/s)^2}{50\ m}$

$a=8\ m/s^2$

So, the centripetal acceleration of the car is $8\ m/s^2$. Hence, this is the required solution.