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KiRa [710]
3 years ago
7

A -kilogram car travels at a constant speed of 20. meters per second around a horizontal circular track. The diameter of the tra

ck is meters. The magnitude of the car's centripetal acceleration is:_______
Physics
1 answer:
Tatiana [17]3 years ago
4 0

Answer:

The centripetal acceleration of the car is 8\ m/s^2.

Explanation:

Let the mass of the car, m=10^3\ kg

Diameter of the circular path, d = 100 m

Speed of car, v = 20 m/s

Radius, r = 50 m

When an object moves in a circular path, the centripetal acceleration acts on it. It is given by :

a=\dfrac{v^2}{r}

a=\dfrac{(20\ m/s)^2}{50\ m}

a=8\ m/s^2

So, the centripetal acceleration of the car is 8\ m/s^2. Hence, this is the required solution.

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Answer:

Normal force on the box and the normal force on the table by the box.

Explanation:

a)The force of kinetic friction on the box and the force applied to the box by the one pushing it:  This pair of forces is compared by Newton's second law.

b)None of these are interaction pairs: If there is a couple of interaction

c)Normal force on the box and the normal force on the table by the box: We know that this pair of forces are equal in magnitude due to Newton's third law, or, the principle of action and reaction, which establishes that when two bodies interact, equal forces and opposite senses appear in each of them.

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FAB = - FBA

FAB: It is the force of action of A on B .

FBA: It is the reaction force of B on A

d)Normal force on the box and the weight of the box: This pair of forces is compared by Newton's second law.

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I.i = j.j = 1
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(-2i - 5j)(i -4j)
= (-2i).i + (-2i).(-4j) + (-5j).i + (-5j).(-4j)
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