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Westkost [7]
3 years ago
10

When a bat hits a ball, the impulse is what?

Physics
2 answers:
Rama09 [41]3 years ago
7 0
The answer is c. The force multiplied by the time the objects are in contact. Hope this helps! :)
german3 years ago
4 0
I believe the answer is C


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Joe drove at the speed of 45 miles per hour for a certain distance. He then drove at the speed of 55 miles per hour for the same
Snowcat [4.5K]

Answer:

v_{avg} = 49.5 mph

Explanation:

Let the distance moved by Joe is "d"

so the time taken by him to drove it by speed 45 mph is given as

t_1 = \frac{d}{v_1}

t_1 = \frac{d}{45}

now the same distance is traveled by him with speed 55 mph

so the time taken by him

t_2 = \frac{d}{55}

so total time taken by him for complete distance 2d

t = t_1 + t_2

t = \frac{d}{45} + \frac{d}{55}

t = 0.0404 d

now the average speed is given as

v_{avg} = \frac{2d}{t}

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2 years ago
A planet has a gravitational acceleration on its surface of 2.2 times Earth's gravitational acceleration on its surface. The pla
lesantik [10]

Answer:

The mass of the planet is 55 times the mass of earth.

Explanation:

From the inverse-square gravitation law,

F = (GMm/r²)

If the weight of a body (the force with which the earth attracts a body to its centre) is to be calculated,

F = mg

m = mass of the body,

g = acceleration due to gravity

mg = (GMm/r²)

G = Gravitational constant

M = mass of the earth

m = mass of body

r = distance between the body and the centre of the earth = radius of the earth

The acceleration due to gravity is given by

g = (GM/r²)

Making the mass of the earth, the subject of formula

M = (gr²/G) (eqn 1)

So, the planet described,

Let the acceleration due to gravity on the planet be g₁

Mass of the planet be M₁

Radius of the planet be r₁

g₁ = 2.2g

r₁ = 5r

M₁ = ?

Note that the gravitational constant is the same for both planets.

So, we can write a similar expression for the planet's acceleration due to gravity

g₁ = (GM₁/r₁²)

Substituting all the parameters known in terms of their corresponding earth values

2.2g = [GM₁/(5r)²]

2.2g = [GM₁/25r²]

M₁ = (55gr²/G)

Recall the expression for the mass of the earth

M = (gr²/G)

M₁ = 55 M

The mass of the planet, in terms of Earth masses = 55M

The mass of the planet is 55 times the planet of earth.

Hope this Helps!!!

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