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3 years ago

When a bat hits a ball, the impulse is what?

Physics

2 answers:

Rama09 [41]3 years ago

7 0

The answer is c. The force multiplied by the time the objects are in contact. Hope this helps! :)

german3 years ago

4 0

I believe the answer is C

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four equal charges of +3microcolumb are placed at the four corners of a square that is 40cm on a side. Find the force on any one

Reil [10]

Answer:

i can see your question

pls fast

6 0

3 years ago

w strong are you? Could you turn a moving car with just your own strength? No way! If a normal driver inputs about 50 N of force

malfutka [58]

The mechanical advantage of a simple machine is the measure of its amplified force gain.

The mechanical advantage is defined as the force amplified by a machine to the force required to generate such output.

$Mathematically\ mechanical\ advantage\ MA=\frac{F_{o}} {F_{i}}$

$F_{o} \ and\ F_{i}$ are the amplified force and applied force. We may also consider them as output and input force.

In the given question, the force given to the steering wheel is 50 N.

The output force produced by the steering wheel is 3750 N.

Hence the mechanical advantage will be-

$MA=\frac{F_{o}} {F_{i}}$

$=\frac{3750\ N}{50\ N}$

$=75$ [ans]

3 0

3 years ago

Alkaline batteries have the advantage of putting out constant voltage until very nearly the end of their life. How long will an

Sidana [21]

Answer:

Explanation:

Voltage, V = 1.58 V

Power, P = 1 W

1 A.h

Charge, Q = 1 A.h = 1 x 3600 A.s = 3600 C

Power x time = Voltage x charge

1 x t = 1.58 x 3600

t = 1.58 x 3600 second

t = 1.58 hours

8 0

3 years ago

A car approaches you at a constant speed, sounding its horn, and you hear a frequency of 76 Hz. After the car goes by, you hear

Talja [164]

Answer:

70.07 Hz

Explanation:

Since the sound is moving away from the observer then

$f_o = f_s\frac {(v+vs)}{v}$ and $f_o = f_s\frac {(v-vs)}{v}$ when moving towards observer

With $f_o$ of 76 then taking speed in air as 343 m/s we have

$76 = f_s\times\frac {(343-vs)}{343}$

$f_s=\frac {343\times 76}{343-v_s}$

Similarly, with $f_o$ of 65 we have

$65 = f_s\times\frac {(343+vs)}{343}\\f_s=\frac {343\times 65}{343+v_s}$

Now

$f_s=\frac {343\times 65}{343+v_s}=\frac {343\times 76}{343-v_s}$

v_s=27.76 m/s

Substituting the above into any of the first two equations then we obtain

$f_s=70.07 Hz$

4 0

3 years ago

What real-world examples show no work being done? Can you think of examples other than resisting the force of gravity?

GalinKa [24]

-- pushing on a brick wall

-- standing on your little brother's back so that he can't get up

-- taking a nap while on the job

-- squeezing anything that doesn't yield to your squeeze, such as a glass bottle or your girl friend

-- watching TV

-- solving math problems in your head

-- making pictures out of clouds in the sky

8 0

3 years ago