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telo118 [61]
2 years ago
12

A 0.10 kg mass is oscillating at a small angle from a light string of length 0.10 m.

Physics
1 answer:
cupoosta [38]2 years ago
5 0

Answer:

tough

Explanation:

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The equation of the car is given by the equation,

                          x(t) = 2.31 + 4.90t² - 0.10t⁶

If we are going to differentiate the equation in terms of x, we get the value for velocity.

                  dx/dt = 9.8t - 0.6t⁵

Calculate for the value of t when dx/dt = 0.

                 dx/dt = 0 = (9.8 - 0.6t⁴)(t)

The values of t from the equation is approximately equal to 0 and 2. 

If we substitute these values to the equation for displacement,

(0)   , x = 2.31 + 4.90(0²) - 0.1(0⁶) = 2.31

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Thus, the positions at the instants where velocity is zero are 2.31 and 15.51 meters. 
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