A fixed electric space heater wired by a cable with an ampacity of 30 A should draw a maximum current of A. 30 A. B. 24 A. C. 15
1 answer:
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Answer:
v₂ = 176.24 m/s
Explanation:
given,
angle of projectile = 45°
speed = v₁ = 150 m/s
for second trail
speed = v₂ = ?
angle of projectile = 37°
maximum height attained formula,
now,
now, equating both the equations
v₂² = 31061.79
v₂ = 176.24 m/s
velocity of projectile would be equal to v₂ = 176.24 m/s
We divide the thin rectangular sheet in small parts of height b and length dr. All these sheets are parallel to b. The infinitesimal moment of inertia of one of these small parts is
where
Now we find the moment of inertia by integrating from
to 
The moment of inertia is
(from (-a/2) to
(a/2))
where
Now we find the moment of inertia by integrating from
The moment of inertia is