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3 years ago

A position-time graph of a spring is shown here. What is the period of the spring's motion.

Physics

1 answer:

Alchen [17]3 years ago

8 0

Answer:C

Explanation:

IAM SURE

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To Mr. H's disgust, a 450-g black crow is raiding the recently-filled bird feeder. As Mr. H runs out the back door with his broo

bagirrra123 [75]

Answer:

Actually it's 2.50 m/s, sorry

Explanation:

It is solved by using momentum conservation equation

combined mass of crow and feeder = 450+670=1120 gm

let the recoil speed of feeder be v m/s

Then applying momentum conservation we get;

1120×1.5 = 670×v

v= 2.50 m/s

the speed at which the feeder initially recoils backwards = 2.50 m/s

5 0

3 years ago

A child has an ear canal that is 1.3 cm long. Assume the speed of sound is v = 344 m/s.

kap26 [50]

Answer:

The frequencies are $(f, f_1) = (6615.4 \ Hz , 19846.2\ Hz)$

Explanation:

From the question we are told that

The length of the ear canal is $l = 1.3 \ cm =\frac{1.3}{100} = 0.013 \ m$

The speed of sound is assumed to be $v_s = 344 \ m/s$

Now taking look at a typical ear canal we see that we assume it is a closed pipe

Now the fundamental harmonics for the pipe(ear canal) is mathematically represented as

$f = \frac{v_s}{4 * l }$

substituting values

$f = \frac{344}{4 * 0.013 }$

$f = 6615.4 \ Hz$

Also the the second harmonic for the pipe (ear canal) is mathematically represented as

$f_1 = \frac{3v_s}{4 * l}$

substituting values

$f_1 = \frac{3 * 344}{4 * 0.013}$

$f_1 = 19846.2 \ Hz$

Given that sound would be loudest in the pipe at the frequency, it implies that the child will have an increased audible sensitivity at this frequencies

6 0

2 years ago

A 200.0 kg piano is elevated by a crane to a height of 10.0 meters above a sidewalk. If the rope holding the piano breaks, what

Nitella [24]

All that business about the crane and the rope and the falling
is only there to confuse us.

The piano ended up 5 meters above the ground.

   Potential energy = (mass) (gravity) (height)

   = (200 kg) (9.81 m/s²) (5 m)

   = (200 · 9.81 · 5) (kg-m²/s²)

   = 9,810 joules .

5 0

2 years ago

Please help i’ll mark you

suter [353]

Answer:

What should I do. reply quickly for a quick answer

8 0

1 year ago

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Define torque qualitatively and quantitatively.

abruzzese [7]

When you use a wrench to tighten or loosen a nut on a bolt, you are applying torque. It is measured in units of force times distance. A force of F newtons pulling on a handle of L meters in length would supply a torque of F L newton-meters. More technically, torque is the vector cross product of force times perpendicular distance from the object, F x r = F r sin @

4 0

2 years ago

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