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aleksandrvk [35]
3 years ago
13

At constant pressure, which of these systems do work on the surroundings? Check all that apply.

Chemistry
1 answer:
MariettaO [177]3 years ago
5 0
A(g) + B(g) → 3C(g)

This is because the volume of gas after reaction is greater than that before the reaction (because there are more moles in the product than in the reactants) so the system's boundary will have to expand in order to maintain constant pressure; this means that the system will do work on its surroundings.
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Explain the units and how to solve the following metric conversion then solve the metric conversion by filling in the blank 12KM
LiRa [457]

Answer:- 12 km = 12000 m

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5 0
3 years ago
34. 3.15 mol of an unknown solid is placed into enough water to make 150.0 mL of solution. The solution's temperature increases
Digiron [165]

Answer:

ΔH = 2.68kJ/mol

Explanation:

The ΔH of dissolution of a reaction is defined as the heat produced per mole of reaction. We have 3.15 moles of the solid, to find the heat produced we need to use the equation:

q = m*S*ΔT

<em>Where q is heat of reaction in J,</em>

<em>m is the mass of the solution in g,</em>

<em>S is specific heat of the solution = 4.184J/g°C</em>

<em>ΔT is change in temperature = 11.21°C</em>

The mass of the solution is obtained from the volume and the density as follows:

150.0mL * (1.20g/mL) = 180.0g

Replacing:

q = 180.0g*4.184J/g°C*11.21°C

q = 8442J

q = 8.44kJ when 3.15 moles of the solid react.

The ΔH of the reaction is:

8.44kJ/3.15 mol

= 2.68kJ/mol

5 0
3 years ago
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