Answer:
The moles present in 60 g of calcium are 1.5 moles.
Answer:
a) heat it from 23.0 to 78.3
q = (50.0 g) (55.3 °C) (2.46 J/g·°C) =
b) boil it at 78.3
(39.3 kJ/mol) (50.0 g / 46.0684 g/mol) =
c) sum up the answers from the two calculations above. Be sure to change the J from the first calc into kJ
Explanation:
Answer:
In order most reactive to least reactive:
D
B
A
C
Explanation:
Answer:
0.067 M
Explanation:
Given data:
Volume of solution = 1.00 L
Mass of BaCl₂ = 14 g
Molarity of solution = ?
Solution:
Molarity is used to describe the concentration of solution. It tells how many moles are dissolve in per litter of solution.
Formula:
Molarity = number of moles of solute / L of solution
Now we will calculate the number of moles first.
Number of moles = mass/ molar mass
Number of moles = 14 g/ 208.23 g/mol
Number of moles = 0.067 mol
Now we will calculate the molarity.
Molarity = 0.067 mol / 1.00 L
Molarity = 0.067 M ( mol/L=M)
Answer:
You can see that it is an endothermic reaction or heat is being absorbed for the change from magnesium to magnesium oxide. So it is an endothermic reaction. So these are the four reasons why we can say that burning of magnesium ribbon in the air is considered a chemical change.
Explanation:
hope it help
