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Alexandra [31]
2 years ago
8

Help!!!! please!!! i’m not sure what the answer is for both questions please

Physics
1 answer:
n200080 [17]2 years ago
7 0

Answer:

a.) 600N

b.) 2 m/s^2

Explanation:

a.)

In order to solve for the needed force, you must use Newton's 2nd law which states that a force is equal to mass multiplied by acceleration.

Basically: Force = mass * acceleration ; F = ma

Since both mass and acceleration are already given, just plug them into the formula and solve for force:

Mass = 200kg

Acceleration = 3m/s^2

F = m * a = 200 * 3 = 600kg * m/s^2 = 600N

b.)

In order to find the acceleration, like the hint already says, you need to find the net force first and then use Newton's 2nd law.

To calculate net force:

Since both forces are parallel (affect the same axis) and in opposite directions, you can subtract the two in order to find resultant magnitude. The resultant direction is the direction of the force with the large magnitude.

Net Force: 8N - 4N = 4N

Net Force Direction: since 8N > 4N, the direction is in the same direciton as the 8N force = Left

Finally, you find acceleration using newton's 2nd law, F = ma.

Since you already know mass and net force, plug in to solve for acceleration:

4N = 2kg * a

a = 4 N / 2kg = 2m/s^2

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3 years ago
Two blocks, joined by a string, have masses of 6.0 and 9.0 kg. They rest on a frictionless, horizontal surface. A second string,
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Answer:

T= 27 N

Explanation:

Assuming that the string joining both masses is massless  and inextensible, both masses accelerate at the same rate.

So, we can treat to both masses as a single system, and apply Newton's 2nd Law to both masses.

In this way, we can get the value of the acceleration without taking into account the tension in the string, as it is an internal force (actually a action-reaction pair).

Newton's 2nd law is a vector equation, so we can decompose the forces along perpendicular axis in order to convert it in two algebraic equations.

We can choose one axis as parallel to the horizontal surface (we call it x-axis, being the positive direction the one of  the movement of the blocks due to the horizontal force applied to the 6.0 kg block), and the other, perpendicular to it, so it is vertical (we call y-axis, being the upward direction the positive one).

Taking into account the forces acting  on both masses, we can write both equations as follows:

Fy = N- (m₁+m₂)*g = 0 (as there is no movement in the vertical direction)

Fx = Fh = (m₁ + m₂) * a ⇒ 45 N = 15.0 kg * a

⇒ a = 45 N / 15.0 kg = 3 m/s²

Now, in order to get the value of the tension T, we can choose as our system, to any mass, and apply Newton's 2nd Law again.

If we choose to the mass of 6.0 kg, in the horizontal direction, there are two forces acting on it, in opposite directions: the  horizontal applied force of 45 N, and the tension in the string that join both masses.

The difference of both forces, must be equal to the mass (of this block only) times the acceleration, as follows:

F- T = m₂* a ⇒ 45 N - T = 6.0 kg * 3 m/s²

⇒ T = 45 N -18 N = 27 N

We could have arrived to the same result taking the 9.0 Kg as our system, as the only force acting in the horizontal direction is just the tension in the string that we are trying to find out, as follows:

F = m₁*a = 9.0 kg* 3 m/s² = 27 N

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