What happens to reactants molecules when forming product molecules?

1 answer:

7 0

Reactant molecules are any substance that goes into a reaction. When forming product molecules, the reactant molecules combine and create a new molecule (i.e. the combination of methane and oxygen can make carbon dioxide and water).

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Compare rutherford's expected outcome of the gold-foil experiment with the actual outcome.

iragen [17]

Rutherford was one of the early scientists who worked on the atomic model. Before his discovery of the nucleus, the widely accepted theory was J.J Thomson's Plum Pudding Model. In this model, all the protons, electrons and neutrons are in the nucleus. But the electrons are more in number such that the electrons act as the 'pudding' and the proton and nucleus the 'plum'. This was Rutherford's hypothesis in his gold foil experiment. In order to test the Plum Pudding model, he hypothesized that when a beam of light is aimed at the atom, it would not diffract because the charges in the nucleus are well-distributed. However, his experiment disproved Thomson's model. Some light indeed passed through but a few was diffracted back to the source. He concluded that this was because there is a dense mass inside the atom called nucleus. Thus, from there on, he proposed the model that the electrons are orbiting around the nucleus.

6 0

2 years ago

Any solid that forms in a liquid during a chemical reaction is called a

Nimfa-mama [501]

<span>it is called precipitant</span>

7 0

3 years ago

Read 2 more answers

How many moles are in 5.6x1025 molecules of calcium oxide?

Vlad1618 [11]

Answer:

<h2>93.02 moles</h2>

Explanation:

To find the number of moles in a substance given it's number of entities we use the formula

$n = \frac{N}{L} \\$

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question we have

$n = \frac{5.6 \times {10}^{25} }{6.02 \times {10}^{23} } \\ = 93.023...$

We have the final answer as

<h3>93.02 moles</h3>

Hope this helps you

8 0

2 years ago

What is the formal charge of nitrogen in no2cl

Gre4nikov [31]

Answer:

The formal charge on nitrogen in $NO_{2}Cl$ is +1.

Explanation:

The structure of $NO_{2}Cl$ is as follows.

(In attachment)

$Formal\, charge = Valence\, electron - (nonbonding\, electrons + \frac{Bonding\,electrons}{2})$

From the structure, Nitrogen has no non bonding electrons. Nitrogen has four bonds and each bond corresponds to 2 electrons. Hence, nitrogen have eight bonding electrons and five valence electrons.

$Formal\,charge\,on\,nitrogen = 5-[0+ \frac{8}{2}]= +1$