Answer and Explanation:
The answer is solution. However, single-phase alloys are solid metal solutions, and colloidal suspensions are homogenous mixtures that are not solutions. Homogenized milk, for example, is a colloidal suspension that technically meets the definition of a homogenous mixture because the milk fats, though immiscible with the whey (the aqueous phase), are tiny beads evenly distributed through the whey, and do not separate according to density, as they do in non-homogenized milk.
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Answer:
160.3g
Explanation:
We know the equation:
No of moles = mass ÷ Mass of element
We need to find the mass, so make mass the subject of the formula.
Mass = No. of moles × mass of element
Mass = 5 × 32.06
Mass = 160.3g
Answer:
A hydrogen bonding is a bond class that is produced from the attraction existing in a hydrogen atom and an oxygen, fluorine or nitrogen atom with a negative charge. This attraction, meanwhile, is known as dipole-dipole interaction and links the positive pole of one molecule with the negative pole of another.
Explanation:
The hydrogen atom, which has a positive charge, is known as the donor atom, while the oxygen, fluorine, chlorine or nitrogen atom is the bond acceptor atom. In the substance in which they are most effective is in the water.
Hydrogen bonds have only one third of the strength of covalent bonds, but they have important effects on the properties of the substances in which they occur, especially in terms of melting and boiling points in crystal structures.
The required mass of calcium bromide is 35.98 grams.
<h3>What is molarity?</h3>
Molarity is any solution is define as the number of moles of solute present in per liter of solution as;
M = n/V, where
- M = molarity = 4M
- V = volume = 45mL = 0.045L
Moles will be calculated by using the above equation as:
n = (4)(0.045) = 0.18 mole
Relation between the mass and moles of any substance will be represented as:
n = W/M, where
- W = given mass
- M = molar mass
Mass of CaBr₂ = (0.18mol)(199.89g/mol) = 35.98g
Hence required mass of CaBr₂ is 35.98 grams.
To know more about molarity, visit the below link:
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Given :
Moles of Na : 1.06
Moles of C : 0.528
Moles of O : 1.59
To Find :
The empirical formula of the compound.
Solution :
Dividing moles of each atom with the smallest one i.e 0.528 .
So,
Na : 1.06/0.528 = 2.007 ≈ 2
C : 0.528/0.528 = 1
O : 1.59/0.528 = 3.011 ≈ 3
Rounding all them to nearest integer, we will get the number of each atom in the empirical formula.
So, empirical formula is
.
Hence, this is the required solution.