Answer:
An earthquake happens by the child being born from fat mama
Explanation:
Answer:
2= its color
Explanation:
Transition elements are present in the middle of periodic table. These are d-block elements.
These are 38 elements.
All transition elements have partially filled d orbitals.
They showed color in compound because of d-d transition.
During the d-d transition electron absorbed the energy and emit the reminder energy. The emission is usually in the form of color light.
The color of ion is complementary to the absorbed color.
The transition elements are used as a catalyst in industries such as polymer, petroleum industries.
They are ductile, conduct heat and electricity.
Th actual yield of the reaction is 24.86 g
We'll begin by calculating the theoretical yield of the reaction.
2Na + Cl₂ → 2NaCl
Molar mass of Na = 23 g/mol
Mass of Na from the balanced equation = 2 × 23 = 46 g
Molar mass of NaCl = 23 + 35.5 = 58.5 g/mol
Mass of NaCl from the balanced = 2 × 58.5 = 117 g
From the balanced equation above,
46 g of Na reacted to produce 117 g of NaCl.
Therefore,
11.5 g of Na will react to produce = (11.5 × 117) / 46 = 29.25 g of NaCl.
Thus, the theoretical yield of NaCl is 29.25 g.
Finally, we shall determine the actual yield of NaCl.
- Theoretical yield = 29.25 g
Actual yield = Percent yield × Theoretical yield
Actual yield = 85% × 29.25
Actual yield = 0.85 × 29.25 g
Actual yield = 24.86 g
Learn more about stoichiometry: brainly.com/question/25899385
<u>Answer:</u> The average atomic mass of the element is 283.291 amu
<u>Explanation:</u>
Average atomic mass of an element is defined as the sum of masses of each isotope each multiplied by their natural fractional abundance.
Formula used to calculate average atomic mass follows:
.....(1)
Mass of isotope 1 = 281.99481 amu
Percentage abundance of isotope 1 = 60.795 %
Fractional abundance of isotope 1 = 0.60795
Mass of isotope 2 = 283.99570 amu
Percentage abundance of isotope 2 = 22.122 %
Fractional abundance of isotope 2 = 0.22122
Mass of isotope 3 = 286.99423 amu
Percentage abundance of isotope 3 = [100 - (60.795 + 22.122)] = 17.083 %
Fractional abundance of isotope 1 = 0.17083
Putting values in equation 1, we get:
![\text{Average atomic mass of element}=[(281.99481\times 0.60795)+(283.99570\times 0.22122)+(286.99423\times 0.17083)]\\\\\text{Average atomic mass of element}=283.291amu](https://tex.z-dn.net/?f=%5Ctext%7BAverage%20atomic%20mass%20of%20element%7D%3D%5B%28281.99481%5Ctimes%200.60795%29%2B%28283.99570%5Ctimes%200.22122%29%2B%28286.99423%5Ctimes%200.17083%29%5D%5C%5C%5C%5C%5Ctext%7BAverage%20atomic%20mass%20of%20element%7D%3D283.291amu)
Hence, the average atomic mass of the element is 283.291 amu
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