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WINSTONCH [101]
3 years ago
10

a charge of 6.4x10^-7 C experiences an electric force of 1.8x10^-1 N what is the electric field strength

Physics
1 answer:
Andreyy893 years ago
5 0
Field strength = force ÷ charge (E=F/Q)

E= 1.8×10^-1 ÷ 6.4×10^-7... to obtain ur answer

the formula is derived from the definition
Electric field : A region in space where a charged body experiences a force.
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Part a which of the following statements are true concerning electromagnetic induction?
maksim [4K]
I had to look for the options and here is my answer:

Based on the actual options attached to this question, the statements that are considered true about electromagnetic induction are the following:
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4 0
3 years ago
A long, thin solenoid has 450 turns per meter and a radius of 1.17 cm. The current in the solenoid is increasing at a uniform ra
sergey [27]

Answer:

\frac{di}{dt}  = 7.31 \  A/s

Explanation:

From the question we are told that  

     The  number of turns is  N =  450 \  turns

      The  radius is  r =  1.17 \ cm =  0.0117 \ m

       The  position from the center consider is  x =  3.45 cm  =  0.0345 m

       The  induced emf is  e  =  8.20 *10^{-6} \  V/m

Generally according to Gauss law

        \int\limits { e } \, dl  =  \mu_o *  N  *  \frac{di}{dt }  *  A

=>    e *  2\pi x  =  \mu_o  *  N  *  \frac{d i }{dt }  *  A

Where A is the  cross-sectional area of the solenoid which is mathematically represented as

                A =  \pi r ^2

=>      e *  2\pi x  =  \mu_o  *  N  *  \frac{d i }{dt }  *  \pi r^2

=>       \frac{di}{dt}  =  \frac{2e * x  }{\mu_o * N  * r^2}ggl;

Here  \mu_o is the permeability of free space with value

          \mu_o  =  4\pi * 10^{-7} \  N/A^2

=>     \frac{di}{dt}  =  \frac{2 *  8.20*10^{-6} *  0.0345  }{ 4\pi * 10^{-7} * 450  * (0.0117)^2}

=>      \frac{di}{dt}  = 7.31 \  A/s

6 0
3 years ago
A vector has an x component of -27.5 units and a y component of 41.4 units. Find the magnitude and direction of this vector. mag
evablogger [386]

Answer:

a.) magnitude __49.7__ unit(s)

b.) direction __123.6°_  counterclockwise from the +x axis

Explanation:

Let Vector is v

x-component of Vector v = x = -27.5 units   (minus sign indicate that x-component is along the minus x-axis )

y-component of Vector v = y = 41.4 units

Magnitude of v = ?

Direction of v = ?

To find the magnitude of the vector

                                     v =\sqrt{x^{2}+y^{2}  }  

                                     v = \sqrt{-27.5^{2}+41.4^{2} }

                                     v = 49.7 units  

To find direction

                                 θ = tan⁻¹(y/x)

                                 θ = tan⁻¹(41.4/-27.5)

                                 θ = -56.4°

This Angle is in the clockwise direction with respect to -x axis.

We need to find Angle counterclockwise from the +x axis.

So,

                                 θ = 180° - 56.4°

                                 θ = 123.6°                

The given vector is in 2nd quadrant

4 0
3 years ago
How fast is a 5 kg object traveling that has 20 kg m/s of momentum?
Jet001 [13]

Answer: 100

Explanation:

7 0
3 years ago
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they will carry it by the stronger person carrying the sides of the wood while the weak person will have his arms underneath to where they dont drop it

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2 years ago
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