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3 years ago

a charge of 6.4x10^-7 C experiences an electric force of 1.8x10^-1 N what is the electric field strength

1 answer:

5 0

Field strength = force ÷ charge (E=F/Q)

E= 1.8×10^-1 ÷ 6.4×10^-7... to obtain ur answer

the formula is derived from the definition
Electric field : A region in space where a charged body experiences a force.

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Part a which of the following statements are true concerning electromagnetic induction?

maksim [4K]

I had to look for the options and here is my answer:

Based on the actual options attached to this question, the statements that are considered true about electromagnetic induction are the following:
-It is possible to induce a current in a closed loop of wire without the aid of a power supply or battery.
-It is possible to induce a current in a closed loop of wire by changing the strength of a magnetic field enclosed by the wire.
-It is possible to induce a current in a closed loop of wire by change the orientation of a magnetic field enclosed by the wire.
-It is possible to induce a current in a closed loop of wire located in a uniform magnetic field by either increasing or decreasing the <span>area enclosed by the loop.</span>

4 0

3 years ago

A long, thin solenoid has 450 turns per meter and a radius of 1.17 cm. The current in the solenoid is increasing at a uniform ra

sergey [27]

Answer:

$\frac{di}{dt} = 7.31 \ A/s$

Explanation:

From the question we are told that

The number of turns is $N = 450 \ turns$

The radius is $r = 1.17 \ cm = 0.0117 \ m$

The position from the center consider is x = 3.45 cm = 0.0345 m

The induced emf is $e = 8.20 *10^{-6} \ V/m$

Generally according to Gauss law

$\int\limits { e } \, dl = \mu_o * N * \frac{di}{dt } * A$

=> $e * 2\pi x = \mu_o * N * \frac{d i }{dt } * A$

Where A is the cross-sectional area of the solenoid which is mathematically represented as

$A = \pi r ^2$

=> $e * 2\pi x = \mu_o * N * \frac{d i }{dt } * \pi r^2$

=> $\frac{di}{dt} = \frac{2e * x }{\mu_o * N * r^2}$ ggl;

Here $\mu_o$ is the permeability of free space with value

$\mu_o = 4\pi * 10^{-7} \ N/A^2$

=> $\frac{di}{dt} = \frac{2 * 8.20*10^{-6} * 0.0345 }{ 4\pi * 10^{-7} * 450 * (0.0117)^2}$

=> $\frac{di}{dt} = 7.31 \ A/s$

6 0

3 years ago

A vector has an x component of -27.5 units and a y component of 41.4 units. Find the magnitude and direction of this vector. mag

evablogger [386]

Answer:

a.) magnitude __49.7__ unit(s)

b.) direction __123.6°_ counterclockwise from the +x axis

Explanation:

Let Vector is v

x-component of Vector v = x = -27.5 units (minus sign indicate that x-component is along the minus x-axis )

y-component of Vector v = y = 41.4 units

Magnitude of v = ?

Direction of v = ?

To find the magnitude of the vector

v = $\sqrt{x^{2}+y^{2} }$

v = $\sqrt{-27.5^{2}+41.4^{2} }$

v = 49.7 units

To find direction

θ = tan⁻¹(y/x)

θ = tan⁻¹(41.4/-27.5)

θ = -56.4°

This Angle is in the clockwise direction with respect to -x axis.

We need to find Angle counterclockwise from the +x axis.

So,

θ = 180° - 56.4°

θ = 123.6°

The given vector is in 2nd quadrant

4 0

3 years ago

How fast is a 5 kg object traveling that has 20 kg m/s of momentum?

Jet001 [13]

Answer: 100

Explanation:

7 0

3 years ago

A wooden log has to carried by two people. If one of them is strong and another weak, how will they carry it? also give reason.

Alborosie

they will carry it by the stronger person carrying the sides of the wood while the weak person will have his arms underneath to where they dont drop it

8 0

2 years ago