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tensa zangetsu [6.8K]
3 years ago
14

The balanced half-reaction in which sulfate ion is reduced to sulfite ion is a __________ process.

Chemistry
1 answer:
harkovskaia [24]3 years ago
8 0

Answer:

Two-electron

Explanation:

You might be interested in
The volume of the granite as
Trava [24]

The volume of the granite as determined by water displacement is 9.35 mL. This value in cm³ is 9.35cm³.

<h3>How to calculate volume in cm³?</h3>

The conversion factor of mL and cm³ is given as follows: 1 mL = 1 cm³

According to this question, the volume of the granite as determined by water displacement is 9.35 mL.

This value in cm³ can be converted as follows:

9.35mL × 1 = 9.35cm³

Therefore, the volume of the granite as determined by water displacement is 9.35 mL. This value in cm³ is 9.35cm³.

Learn more about volume at: brainly.com/question/1578538

#SPJ1

8 0
2 years ago
Concept Review<br> 14.11. Can a reaction that is not reversible achieve chemical equilibrium?
MakcuM [25]

Answer:

No

Explanation:

Chemical equilibrium is reached by the forward reaction rate equaling the reverse reaction rate. If the reaction is not reversible, this could not occur.

7 0
3 years ago
A mixture of two compounds, A and B, was separated by extraction. After the compounds were dried, their masses were found to be:
Arlecino [84]

Answer:

The percent recovery from re crystallization for both compounds A and B is 69.745 and 81.44 % respectively.

Explanation:

Mass of compound A in a mixture  = 119 mg

Mass of compound A after re-crystallization = 83 mg

Percent recovery from re-crystallization :

\frac{\text{Mass after re-crystallization}}{\text{Mass before re-crystallization}}\times 100

Percent recovery of compound A:

\frac{83 mg}{119 mg}\times 100=69.74\%

Mass of compound B in a mixture  = 97 mg

Mass of compound B after re-crystallization = 79 mg

Percent recovery of compound B:

\frac{79 mg}{97 mg}\times 100=81.44\%

3 0
3 years ago
What is the ph of a soft drink in which the major buffer ingredients are 6.6 g of nah2po4 and 8.0 g of na2hpo4 per 355 ml of sol
Alex777 [14]
The Relative Formula Mass of NaH2PO4 is 120 g/mol
Therefore, the number of moles = 6.6/120
                                                   = 0.055 moles of NaH2PO4 which is also equal to the number of moles of H2PO4.
[H2PO4-] = Number of moles oof H2PO4-/Volume of the solution in L
  = 0.055/ ( 355 ×10^-3)
  = 0.155 M
Na2HPO4 undergoes complete dissociation as follows;
Na2HPO4 (aq)= 2Na+ (aq) + HPO4^2- (aq)

1 mole of Na2HPO4 = 142 g/mol
Therefore; number of moles = 8.0/142
                                             = 0.0563 moles
 [HPO4 ^-2] is given by no of moles HPO4^2- /volume of the solution in L
     = 0.0563/(355×10^-3)
     =  0.1586 M
Both H2PO4^2- and HPO4^2- are weak acids the undergoes partial dissociation 
Ka of H2PO4- = 6.20 × 10^-8
 [H+] =Ka*([H2PO4-]/[HPO4(2-)]
        = (6.20 ×10^-8)×(0.155/0.1586)
        = 6.059 ×10^-8 M
pH = - log[H+]
     = - log (6.059×10^-8)
     = 7.218

5 0
3 years ago
9474 millimeters to centimeters using scientific notation showing work
puteri [66]

Answer:

9.474 x 10^2

Explanation:

ok. first you have to get the value in the required unit so 9474mm/(10mm/cm) = 947.4 so scientific notation states that the number must be raised to any power of an integer and the value of the number being raised must be less than than 10 and more than or equal to 1

so it must have one digit in front so.. 947.4 becomes 9.474 and because you move 2 places to the left, ur power is positive 2

and proof 10^2 is 100 so multiply 9.474 by 100 and u will get 947.4 cm which is also 9474 mm

8 0
3 years ago
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