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3 years ago

Which function represents a reflection of f(x) = Three-sevenths(2)x over the x-axis?

Mathematics

2 answers:

NemiM [27]3 years ago

9 0

Given:

The given function is $f(x)=\frac{3}{7}(2)^{x}$

We need to determine the reflection of f(x) over the x - axis

Reflection over x - axis:

The translation rule to reflect over the x - axis is given by

$(x, y) \rightarrow(x,-y)$

Reflecting the function over the x - axis, we get;

$-y=\frac{3}{7}(2)^{x}$

Multiplying -1 to both sides of the equation, we have;

$y=-\frac{3}{7}(2)^{x}$

This can be written as

$g(x)=-\frac{3}{7}(2)^{x}$

Hence, the reflection of the function over the x - axis is $g(x)=-\frac{3}{7}(2)^{x}$

Thus, Option A is the correct answer.

Gekata [30.6K]3 years ago

8 0

Answer:

Step-by-step explanation:

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5. Each year a tree farm grows 40 more trees than the number of trees grown the previous year. The farm sells all of their trees

Veronika [31]

Answer:

1710 trees up to 2016 (not including 2016)

2100 trees up to 2016 (including 2016)

Step-by-step explanation:

Given that

Farm started with 30 trees in 2007.

Every year 40 more trees than the previous year.

It is actually an Arithmetic Progression (AP) with

First term, a = 30 and

Common Difference, d = 40

The AP will look like:

30, 70, 110, 150, ....

We have to find the sum of this AP upto 9 terms and 10 terms:

9 terms sum will give us the total number of trees up to 2016 (not including 2016).

10 terms sum will give us the total number of trees up to 2016 (including 2016).

Formula for sum of 'n' terms of an AP:

$S_n=\dfrac{n}{2}(2a+(n-1)d)\\\Rightarrow S_9=\dfrac{9}{2}(2\times 30+(9-1)40)\\\Rightarrow S_9=\dfrac{9}{2}(60+320)\\\Rightarrow S_9=\dfrac{9}{2}(380)\\\Rightarrow S_9=9 \times 180 = 1710$

$S_{10}=\dfrac{10}{2}(2\times 30+(10-1)40)\\\Rightarrow S_{10}=5(60+360)\\\Rightarrow S_{10}=5 \times 420\\\Rightarrow S_{10}=2100$

1710 trees up to 2016 (not including 2016)

2100 trees up to 2016 (including 2016)

4 0

3 years ago

Can i have some help (marked an Brainllest)

Marysya12 [62]

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3 years ago

Triangle A″B″C″ is formed using the translation (x + 2, y + 0) and the dilation by a scale factor of one half from the origin. W

lesya692 [45]

Answer:

A)segment A"B"= AB / 2

Step-by-step explanation:

Triangle A″B″C″ is formed using the translation (x + 2, y + 0) and the dilation by a scale factor of one half from the origin. Which equation explains the relationship between segment AB and segment A"B"?

coordinate plane with triangle ABC at A(-3, 3), B(1, -3), and C(-3, -3)

A)segment A"B"= AB / 2

B)segment AB = segment A"B"/ 2

C)segment AB / segment A"B"= 1/2

D)segment A"B" / segment AB = 2

A"B" = AB / 2

Because

1. translations do not change the lengths of segments, so (x+2, y+0) preserves the length of AB, i.e. mA'B' = mAB

2. Dilation causes the new segment to be transformed to a new length according to the old length * the scale factor of (1/2).

Therefore A"B" = (1/2)AB, or AB/2.

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3 years ago

Find a “solution” for an equation with two variables. Tell me an x, y ordered pair that is a solution (answer) for this equation

Finger [1]

Answer:

Step-by-step explanation:

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4 0

3 years ago

Help pls look at the picture

Alika [10]

Answer:

Option A: $-\frac{4}{3}$ is the correct answer.

Step-by-step explanation:

Given that:

Slope of the line = $\frac{3}{4}$

Let,

m be the slope of the line perpendicular to the line with slope $\frac{3}{4}$

We know that,

The product of slopes of two perpendicular lines is equals to -1.

Therefore,

$\frac{3}{4}.m=-1\\$

Multiplying both sides by $\frac{4}{3}$

$\frac{4}{3}*\frac{3}{4}m=-1*\frac{4}{3}\\$

m = $-\frac{4}{3}$

$-\frac{4}{3}$ is the slope of the line perpendicular to the line having slope $\frac{3}{4}$

Hence,

Option A: $-\frac{4}{3}$ is the correct answer.

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3 years ago