Answer:
Acceleration a=0.5 m/s²
Explanation:
Given data
Mass m=12,900 kg=1.29×10⁴kg
Thrust of engine F=28,000 N=2.8×10⁴N
gravitational acceleration g=1.67 m/s²
To find
Acceleration
Solution
As we know that
![W_{weigth}=mg\\ W=(1.29*10^{4}kg )(1.67m/s^{2} )\\W=21543N](https://tex.z-dn.net/?f=W_%7Bweigth%7D%3Dmg%5C%5C%20W%3D%281.29%2A10%5E%7B4%7Dkg%20%29%281.67m%2Fs%5E%7B2%7D%20%29%5C%5CW%3D21543N)
The net force can be given as
![F_{net}=F_{thrust}-W\\F_{net}=(2.8*10^{4}-21543)N\\ F_{net}=6457 N](https://tex.z-dn.net/?f=F_%7Bnet%7D%3DF_%7Bthrust%7D-W%5C%5CF_%7Bnet%7D%3D%282.8%2A10%5E%7B4%7D-21543%29N%5C%5C%20%20%20F_%7Bnet%7D%3D6457%20N)
From Newtons second law of motion we know that
![F=ma\\a=F/m\\a=\frac{6457N}{12,900kg}\\ a=0.5m/s^{2}](https://tex.z-dn.net/?f=F%3Dma%5C%5Ca%3DF%2Fm%5C%5Ca%3D%5Cfrac%7B6457N%7D%7B12%2C900kg%7D%5C%5C%20a%3D0.5m%2Fs%5E%7B2%7D)
Answer:
A massive object (like a galaxy cluster) bends the light from an object (like a quasar) that lies behind it.
Explanation:
A massive object, like a galaxy cluster, is able to deform the space-time shape as a consequence of its own gravity, so the light that it is coming from a source that is behind it in the line of sight will be bend or distorts in a way that will be magnified, making small arcs around the cluster with the image of the background object.
This technique is useful for astronomers since they make research of faraway objects (at hight redshift) that otherwise will difficult to detect with a telescope.
Explanation:
The hydraulic system works on the principle of Pascal's law which says that the pressure in an enclosed fluid is uniform in all the directions. ... As the pressure is same in all the direction, the smaller piston feels a smaller force and a large piston feels a large force.
Convection is the process of heat transfer in fluids by the actual motion of matter. It happens in liquids and gases. It may be natural or forced. It involves a bulk transfer of portions of the fluid.
Hope that helps
Answer:
![F=5.8\times 10^{8}\ N](https://tex.z-dn.net/?f=F%3D5.8%5Ctimes%2010%5E%7B8%7D%5C%20N)
![F=35.57\times 10^{21}\ N](https://tex.z-dn.net/?f=F%3D35.57%5Ctimes%2010%5E%7B21%7D%5C%20N)
Explanation:
Given that
Intensity I
![I= 1.39\ KW/m^2](https://tex.z-dn.net/?f=I%3D%201.39%5C%20KW%2Fm%5E2)
![Speed\ of \ light = 2.99\times 10^8\ m/s](https://tex.z-dn.net/?f=Speed%5C%20of%20%5C%20light%20%3D%202.99%5Ctimes%2010%5E8%5C%20m%2Fs)
Radius of earth,R = 6370 Km
We know that surface area of earth, A
![A=\pi R^2](https://tex.z-dn.net/?f=A%3D%5Cpi%20R%5E2)
![A=\pi (6370\times 10^3)^2\ m^2](https://tex.z-dn.net/?f=A%3D%5Cpi%20%286370%5Ctimes%2010%5E3%29%5E2%5C%20m%5E2)
![A=1.27\times 10^{14}\ m^2](https://tex.z-dn.net/?f=A%3D1.27%5Ctimes%2010%5E%7B14%7D%5C%20m%5E2)
As we know that pressure due to intensity given as
![P=\dfrac{I}{V}](https://tex.z-dn.net/?f=P%3D%5Cdfrac%7BI%7D%7BV%7D)
V =Velocity of light
![V=3\times 10^8\ m/s](https://tex.z-dn.net/?f=V%3D3%5Ctimes%2010%5E8%5C%20m%2Fs)
![P=\dfrac{1.39\times 1000}{=3\times 10^8}](https://tex.z-dn.net/?f=P%3D%5Cdfrac%7B1.39%5Ctimes%201000%7D%7B%3D3%5Ctimes%2010%5E8%7D)
![P=4.6\times 10^{-6}\ Pa](https://tex.z-dn.net/?f=P%3D4.6%5Ctimes%2010%5E%7B-6%7D%5C%20Pa)
We know that force F
F = P .A
![F=4.6\times 10^{-6}\times 1.27\times 10^{14}\ N](https://tex.z-dn.net/?f=F%3D4.6%5Ctimes%2010%5E%7B-6%7D%5Ctimes%201.27%5Ctimes%2010%5E%7B14%7D%5C%20N)
![F=5.8\times 10^{8}\ N](https://tex.z-dn.net/?f=F%3D5.8%5Ctimes%2010%5E%7B8%7D%5C%20N)
b)Gravitational force F
![F=G\dfrac{m.M}{r^2}](https://tex.z-dn.net/?f=F%3DG%5Cdfrac%7Bm.M%7D%7Br%5E2%7D)
![M = mass\ of\ sun = 2\times 10^{30} kg\\m = mass\ of\ earth = 6\times 10^{24}kg](https://tex.z-dn.net/?f=M%20%3D%20mass%5C%20of%5C%20sun%20%3D%202%5Ctimes%2010%5E%7B30%7D%20kg%5C%5Cm%20%3D%20mass%5C%20of%5C%20earth%20%3D%206%5Ctimes%2010%5E%7B24%7Dkg)
![r =1.5\times 10^{11}\ m](https://tex.z-dn.net/?f=r%20%3D1.5%5Ctimes%2010%5E%7B11%7D%5C%20m)
![G =6.67\times 10^{-11}Nm^2/kg^2](https://tex.z-dn.net/?f=G%20%3D6.67%5Ctimes%2010%5E%7B-11%7DNm%5E2%2Fkg%5E2)
So F
![F=6.67\times 10^{-11}\times \dfrac{2\times 10^{30}\times 6\times 10^{24}kg}{1.5\times 10^{11}}](https://tex.z-dn.net/?f=F%3D6.67%5Ctimes%2010%5E%7B-11%7D%5Ctimes%20%5Cdfrac%7B2%5Ctimes%2010%5E%7B30%7D%5Ctimes%206%5Ctimes%2010%5E%7B24%7Dkg%7D%7B1.5%5Ctimes%2010%5E%7B11%7D%7D)
![F=35.57\times 10^{21}\ N](https://tex.z-dn.net/?f=F%3D35.57%5Ctimes%2010%5E%7B21%7D%5C%20N)