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Marrrta [24]
3 years ago
15

In the two-stage cooling method, what is the maximum amount of time allowed to cool food from 135 degrees F or more to 70 degree

s F or less?
Physics
1 answer:
Tresset [83]3 years ago
5 0
The problem ask to find the maximum amount of time that is allowed to cool food from 135 degree F or more to 70 degree F or less and the allowed time would be that the food would be cool of is around to 4 to 6 hours. I hope you are satisfied with my answer and feel free to ask for more of you have questions and further clarifications 
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How many oxygen atoms are in Ca (NO3)2
Lapatulllka [165]

There are 6 atoms of oxygen in Ca (NO3)2.

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3 years ago
A car accelerates from rest to 90m/s in 3 seconds. What is the acceleration and how far did it travel?
Inessa [10]

Answer:

Explanation:

1.)acceleration= final velocity-initial velocity/time

90m/s-0m/s /3seconds

=30m/s^2

2.) distance= speed*time

90m/s*3seconds

=270m

4 0
3 years ago
Each vertical column on the periodic table is called a
Morgarella [4.7K]
Vertical columns on the periodic table are called groups.

I hope you like this answer, please Brainliest me, and have a good day and life! :D<span />
3 0
4 years ago
Read 2 more answers
A curve of radius 166 m is banked at an angle of 11°. An 736-kg car negotiates the curve at 81 km/h without skidding. Neglect th
lianna [129]

Answer:

F_n = 7509.33\ N

Explanation:

given,

radius of curve = 166 m

angle of the banked road = 11°

mass of car = 736 Kg

speed of the curve = 81 km/h

                                = 81 x 0.278 = 22.52 m/s

normal force acting on the tires

on tire there will be two force acting on it

first one will be force acting due to weight and the other force acting on the tire is due to centripetal force.

F_n = m g cos \theta+ \dfrac{mv^2}{r} sin \theta

F_n = 736 \times 9.8 \times cos 11^0+\dfrac{736 \times 22.52^2}{166} sin 11^0

F_n = 7080.28+429.047

F_n = 7509.33\ N

6 0
3 years ago
In a physics experiment, two equal-mass carts roll towards each other on a level, low-friction track. One cart rolls rightward a
xz_007 [3.2K]

Answer:

The correct answer is option a.

Explanation:

Conservation of momentum :

m_1u_1+m_2u_2=m_1v_1+m_1v_2

Where :

m_1, m_2 = masses of object collided

u_1,u_2 = initial velocity before collision

v_1,v_2 = final velocity after collision

We have :

Two equal-mass carts roll towards each other.

m_1=m_2=M

Initial velocity of m_1=u_1=2 m/s

Initial velocity of m_2=u_2=-1 m/s (opposite direction)

Final velocity of m_1=v_1=v (same direction )

Final velocity of m_2=v_2=v  (same direction)

M\times 2 m/s+M(-1 m/s)=Mv+Mv

1 m/s=2v

v = 0.5 m/s

rg135

The speed of the carts after their collision is 0.5 m/s.

7 0
4 years ago
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