1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Marrrta [24]
3 years ago
15

In the two-stage cooling method, what is the maximum amount of time allowed to cool food from 135 degrees F or more to 70 degree

s F or less?
Physics
1 answer:
Tresset [83]3 years ago
5 0
The problem ask to find the maximum amount of time that is allowed to cool food from 135 degree F or more to 70 degree F or less and the allowed time would be that the food would be cool of is around to 4 to 6 hours. I hope you are satisfied with my answer and feel free to ask for more of you have questions and further clarifications 
You might be interested in
A circular test track for cars has a circumference of 4.7 km. A car travels around the track from the southernmost point to the
Alika [10]
Well, for the distance traveled, the car goes from the northernmost point to the southernmost point. So, it travels half of the circle's circumference = 4.7/2 = 2.35 km.

For the displacement, by going from the northernmost point to the southernmost point, the car basically just travels the diameter of circle.

So, using the formula: Circumference = 2πr = <span>πd

Hence, the d = C/</span>π = 4.7/<span>π = 1.49605... = 1.5 km (2 significant figures)
Therefore, displacement = 1.5 km</span>
7 0
3 years ago
An aluminum wire with a diameter of 0.115 mm has a uniform electric field of 0.235 V/m imposed along its entire length. The temp
tekilochka [14]

Answer with Explanation:

We are given that

Diameter of coil=d=0.115mm

Radius, r=\frac{d}{2}=\frac{0.115}{2}=0.0575mm=0.0575\times 10^{-3} m

Using 1mm=10^{-3} m

Electric field=E=0.235V/m

T=55 degree C

T_0=20^{\circ} C

\rho_0=2.82\times 10^{-8}\Omega m

\alpha=3.9\times 10^{-3}/C

(a).We know that

\rho=\rho_0(1+\alpha(T-T_0))

Substitute the values

\rho=2.82\times 10^{-8}(1+3.9\times 10^{-3}(55-20))

\rho=3.2\times 10^{-8}\Omega m

(b).Current density,J=\frac{E}{\rho}

Using the formula

J=\frac{0.235}{3.2\times 10^{-8}}=7.3\times 10^6A/m^2

c.Total current,I=JA

Where A=\pi r^2

\pi=3.14

Using the formula

I=7.3\times 10^6\times 3.14\times (0.0575\times 10^{-3})^2

I=0.076A

d.Length of wire=l=2m

V=El

Substitute the values

V=0.235\times 2=0.47 V

5 0
3 years ago
Calculate the net force if the forces are parallel 4N 4N
iogann1982 [59]

Answer:

The net force is zero Newtons (0 N).

Explanation:

If the forces on one side is 4N and the forces on another side are 4N, the forces cancel out and you have a net force of zero. This means the object is at rest or is moving at a constant rate based on the question.

Hope this helps!

5 0
3 years ago
Read 2 more answers
A car moving at 10.0 m/s encounters a depression in the road that has a circular cross-section with a radius of 30.0 m. What is
Dennis_Churaev [7]

Answer:

F = 789 Newton

Explanation:

Given that,

Speed of the car, v = 10 m/s

Radius of circular path, r = 30 m

Mass of the passenger, m = 60 kg

To find :

The normal force exerted by the seat of the car when the it is at the bottom of the depression.

Solution,

Normal force acting on the car at the bottom of the depression is the sum of centripetal force and its weight.

N=mg+\dfrac{mv^2}{r}

N=m(g+\dfrac{v^2}{r})

N=60\times (9.81+\dfrac{(10)^2}{30})

N = 788.6 Newton

N = 789 Newton

So, the normal force exerted by the seat of the car is 789 Newton.

6 0
3 years ago
A big league hitter attacks a fastball! The ball has a mass of 0.16 kg. It is pitched at 38 m/s. After the player hits the ball,
Strike441 [17]
Momentum = (mass) x (velocity)
Original momentum before the hit = 
                   (0.16 kg) x (38 m/s) this way <==
               =             6.08 kg-m/s  this way <==
Momentum after the hit = 
                   (0.16) x (44 m/s) that way  ==>
               =           7.04 kg-m/s  that way ==>
Change in momentum = (6.08 + 7.04) =  13.12 kg-m/s  that way ==> .-----------------------------------------------
Change in momentum = impulse.
                                   Impulse = (force) x (time the force lasted)
                          13.12 kg-m/s  = (force) x (0.002 sec)
  (13.12 kg-m/s) / (0.002 sec)  =  Force
             6,560 kg-m/s² = 6,560 Newtons  =  Force    
                            ( about 1,475 pounds  ! ! ! )
 Hoped this helped!! ☺
4 0
4 years ago
Other questions:
  • The long-term effect of temperature on the polar ice is not fully understood by science. True False
    15·2 answers
  • Most ___ do not carry electricity well.
    13·1 answer
  • You hold a spherical salad bowl 50 cm in front of your face with the bottom of the bowl facing you. The salad bowl is made of po
    13·1 answer
  • A box is sliding down an incline tilted at a 11.6° angle above horizontal. The box is initially sliding down the incline at a sp
    10·1 answer
  • A solenoid with 400 turns has a radius of 0.040 m and is 40 cm long. If this solenoid carries a current of 12 A, what is the mag
    12·1 answer
  • To calculate the heat needed to boil a pot of water at 100C, what do you need to know? A. the mass and latent heat of fusion B.
    9·2 answers
  • Which model of the atom was modeled after the solar system?
    7·1 answer
  • A crossbow is fired horizontally off a cliff with an initial velocity of 15 m/s. If the arrow takes 4s to hit the ground, what i
    13·1 answer
  • What is the mass of an object that has a weight of 110N ?
    15·1 answer
  • A 500 Kg load is lifted through a vertical height of 10m in 25s by a crane. Calculate the power of the crane
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!