Answer:
v = 34.35 m/s
Explanation:
In order to find the speed of the car, when it has traveled 60m, you take into account the Work-Energy theorem, which is given by the following formula:
(1)
W: work done on the roller coaster by the electromagnetic propulsion
m. mass of the roller coaster = 700kg
v2: final speed of the roller coaster = ?
v1: initial speed = 0m/s
you have that the force exerted on the roller depends on x, the distance traveled by the roller. To calculate the work W, you use the following integral:
(2)
where F is given by:
You replace the previous function F in the integral (2) and calculate W:
Next, you solve the equation (1) for v2, and replace the values of all parameters:
The final speed of roller coaster, after it has traveled 60m is 34.35m/s
Answer:
1.44*10^-3m
Explanation:
Given that distance BTW two bright fringes is
DetaY = lambda* L/d
So for second wavelength
Deta Y2= Lambda 2* L/d
=lambda 2 x deta y1/ lambda1
So substituting
= 360 x 10^-9 x (1.6*10^-3/640*10^-9)
1.44*10^ -3m
An electric current will move through in the wire caseing causing more power to be released
D = 0.9 km = 900 m, distance moved
v = 35 nm/s , the speed
v = 35 x 10⁻⁹ m/s
= (35 x 10⁻⁹ m/s)*(365 days/y)*(24*60*60 s/day)
= 1.1038 m/y
The time iaken is
t = d/v
= (900 m)/(1.1038 m/y)
= 815.365 y
Answer: 815.4 y (nearest tenth)
Answer:
Explanation:
Let λ be the required wavelength.
Two fringe patterns will be formed on the screen which will overlap each other. Let 9 th bright fringe of first coincides with 11 th bright fringe of second.
position of 9 the bright fringe of first = 9x 646 x D/d nm
position of 11 th bright fringe of second pattern = 11 x λ x D/d
now , 9 x 646 = 11 x λ
λ = 9 x 646 / 11 = 528.54 nm.