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2 years ago

Which type of circuit is a continuous loop that allows the flow of current along its intended path?

Physics

2 answers:

Lemur [1.5K]2 years ago

7 0

C

Closed circuits allow current to flow

zhannawk [14.2K]2 years ago

5 0

A C) closed circuit is a continuous loop that allows the flow of current along its intended path.

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Suppose that the average speed (vrms) of carbon dioxide molecules (molar mass 44.0 g/mol) in a flame is found to be 2.67 105 m/s

34kurt

Answer:

$T = 1.26 \times 10^8 K$

Explanation:

As we know that rms speed of ideal gas is given by the formula

$v_{rms} = \sqrt{\frac{3RT}{M}}$

here we know that

$v_{rms} = 2.67 \times 10^5 m/s$

molecular mass of gas is given as

$M = 44 g/mol = 0.044 kg/mol$

now from above formula we have

$2.67\times 10^5 = \sqrt{\frac{3(8.31)T}{0.044}}$

now we have

$T = 1.26 \times 10^8 K$

7 0

3 years ago

Two ships leave a harbor at the same time, traveling on courses that have an angle of 110∘ between them. If the first ship trave

Allushta [10]

Answer:

49.07 miles

Explanation:

Angle between two ships = 110° = θ

First ship speed = 22 mph

Second ship speed = 34 mph

Distance covered by first ship after 1.2 hours = 22×1.2 = 26.4 miles = b

Distance covered by second ship after 1.2 hours = 34×1.2 = 40.8 miles = c

Here the angle between the two sides of a triangle is 110° so from the law of cosines we get

a² = b²+c²-2bc cosθ

⇒a² = 26.4²+40.8²-2×26.4×40.8 cos110

⇒a² = 2408.4

⇒a = 49.07 miles

6 0

2 years ago

HELP PLEASE <br> THANK YOU!!

Simora [160]

Kelvin is the answer

4 0

2 years ago

Read 2 more answers

In a semiclassical model of the hydrogen atom, the electron orbits the proton at a distance of 0.053 nm. Part A What is the elec

Bezzdna [24]

Answer with Explanation:

We are given that

$r=0.053 nm=0.053\times 10^{-9} m$

$1 nm=10^{-9} m$

Charge on proton,q= $1.6\times 10^{-19} C$

a.We have to find the electric potential of the proton at the position of the electron.

We know that the electric potential

$V=\frac{kq}{r}$

Where $k=9\times 10^9$

$V=\frac{9\times 10^9\times 1.6\times 10^{-19}}{0.053\times 10^{-9}}$

$V=27.17 V$

B.Potential energy of electron,U= $\frac{kq_e q_p}{r}$

Where

$q_e=-1.6\times 10^{-19} c=$ Charge on electron

$q_p=q=1.6\times 10^{-19} C$ =Charge on proton

Using the formula

$U=\frac{9\times 10^9\times (-1.6\times 10^{-19}\times 1.6\times 10^{-19}}{0.053\times 10^{-9}}$

$U=-4.35\times 10^{-18} J$

8 0

2 years ago

which of the following is not a type of cosmic radiation? gamma-rays, x-rays, sound waves, or cosmic rays

Archy [21]

Answer: sound waves or cosmic rays

Explanation:

Cosmic radiation consist of high energy particles,x-rays and gamma rays produce in space

7 0

2 years ago