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ryzh [129]
3 years ago
11

Which shows a structural formula with a triple bond?

Chemistry
2 answers:
nikdorinn [45]3 years ago
7 0

The answer is: N ≡ N.

Nitrogen (N) is in group 15 of Periodic table of elements and his atomic number is seven, which means that nitrogen has 7 protons and 7 electrons.

Electron configuration of nitrogen atom: ₇N 1s²2s²2p³.

Nitrogen is inert (low reactivity) nonmetal and has five valence electrons.

Nitrogen molecule (N₂) has strong nonpolar triple covalent bond (:N:::N:), that is why it is very stable and have low reactivity.

Elan Coil [88]3 years ago
4 0
C.NTRIPLE BOND N THE THIRD OPTION IS THE ANSWER
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n-Butane (C4H10) is burned with stoichiometric amount of oxygen. Determine the mole fraction of carbon dioxide and water in the
Fudgin [204]

Answer:

See details below

Explanation:

The balanced reaction equation is given below:

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8 0
3 years ago
Following the instructions in your lab manual, you have titrated a 25.00 mL sample of 0.0100 M KIO3 with a solution of Na2S2O3 o
vivado [14]

<u>Answer:</u>

<u>For 1:</u> The amount of potassium iodate that were titrated is 2.5\times 10^{-4} moles

<u>For 2:</u> The amount of sodium thiosulfate required is 1.25\times 10^{-4} moles

<u>Explanation:</u>

  • <u>For 1:</u>

To calculate the number of moles for given molarity, we use the equation:

\text{Molarity of the solution}=\frac{\text{Moles of solute}\times 1000}{\text{Volume of solution (in L)}}

Molarity of KIO_3 solution = 0.0100 M

Volume of solution = 25 mL

Putting values in above equation, we get:

0.0100M=\frac{\text{Moles of }KIO_3\times 1000}{25}\\\\\text{Moles of }KIO_3=\frac{0.0100\times 25}{1000}=0.00025mol

Hence, the amount of potassium iodate that were titrated is 2.5\times 10^{-4} moles

  • <u>For 2:</u>

The chemical equation for the reaction of potassium iodate and sodium thiosulfate follows:

2KIO_3+Na_2S_2O_3\rightarrow K_2S_2O_3+2NaIO_3

By Stoichiometry of the reaction:

2 moles of potassium iodate reacts with 1 mole of sodium thiosulfate

So, 0.00025 moles of potassium iodate will react with = \frac{1}{2}\times 0.00025=0.000125mol of sodium thiosulfate

Hence, the amount of sodium thiosulfate required is 1.25\times 10^{-4} moles

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