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3 years ago

Which shows a structural formula with a triple bond?

Chemistry

2 answers:

nikdorinn [45]3 years ago

7 0

The answer is: N ≡ N.

Nitrogen (N) is in group 15 of Periodic table of elements and his atomic number is seven, which means that nitrogen has 7 protons and 7 electrons.

Electron configuration of nitrogen atom: ₇N 1s²2s²2p³.

Nitrogen is inert (low reactivity) nonmetal and has five valence electrons.

Nitrogen molecule (N₂) has strong nonpolar triple covalent bond (:N:::N:), that is why it is very stable and have low reactivity.

Elan Coil [88]3 years ago

4 0

C.NTRIPLE BOND N THE THIRD OPTION IS THE ANSWER

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Which of the following best describes how further studies supported the work done by Max Planck in the field of quantum mechanic

givi [52]

Answer:

Neils Bohr determined that electrons inhabit distinct energy levels.

Explanation:

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A 50/50 blend of engine coolant and water (by volume) is usually used in an automobile's engine cooling system. If a car's cooli

Diano4ka-milaya [45]

Answer:

$\large \boxed{109.17 \, ^{\circ}\text{C}}$

Explanation:

Data:

50/50 ethylene glycol (EG):water

V = 4.70 gal

ρ(EG) = 1.11 g/mL

ρ(water) = 0.988 g/mL

Calculations:

The formula for the boiling point elevation ΔTb is

$\Delta T_{b} = iK_{b}b$

i is the van’t Hoff factor — the number of moles of particles you get from 1 mol of solute. For EG, i = 1.

1. Moles of EG

$\rm n = 0.50 \times \text{4.70 gal} \times \dfrac{\text{3.785 L}}{\text{1 gal}} \times \dfrac{\text{1000 mL}}{\text{1 L}} \times \dfrac{\text{1.11 g}}{\text{1 mL}} \times \dfrac{\text{1 mol}}{\text{62.07 g}} = \text{159 mol}$

2. Kilograms of water

$m = 0.50 \times \text{4.70 gal} \times \dfrac{\text{3.785 L}}{\text{1 gal}} \times \dfrac{\text{998 g}}{\text{1 L}} \times \dfrac{\text{1 kg}}{\text{1000 g}} = \text{8.88 kg}$

3. Molal concentration of EG

$b = \dfrac{\text{159 mol}}{\text{8.88 kg}} = \text{17.9 mol/kg}$

4. Increase in boiling point

$\rm \Delta T_{b} = iK_{b}b = 1 \times 0.512 \, \, ^{\circ}\text{C} \cdot kg \cdot mol^{-1} \, \times 17.9 \cdot mol \cdot kg^{-1} = 9.17 \, ^{\circ}\text{C}$

5. Boiling point

$\rm T_{b} = T_{b}^{\circ} + \Delta T_{b} = 100.00 \, ^{\circ}\text{C} + 9.17 \, ^{\circ}\text{C} = \mathbf{109.17 \, ^{\circ}C}\\\rm \text{The boiling point of the solution is $\large \boxed{\mathbf{109.17 \, ^{\circ}C}}$}$

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3 years ago

Calculate the moles of 36.030 g of H2O.

lions [1.4K]

Answer: 1.99 mol h20

Explanation:

you have 36.030 g, trying to get it into mols

to get from g to mols, use the molar mass (periodic table)

36.030 g h20 (1 mol/18.02g) = 1.99 mol h20

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2 years ago

Which lists only metalloids?

enot [183]

Answer:

boron (B), germanium (Ge), and tellurium (Te)

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A student is asked to identify and element that is pale yellow brittle solid and does not conduct electricity. At which location

disa [49]

Answer:

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Explanation:

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Hope it help!

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