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3 years ago

Which is the smallest particle into which water (H2O) in a glass can be broken down and still remain water?

Chemistry

2 answers:

TEA [102]3 years ago

6 0

I think it is hydrogen but i might not be right

nika2105 [10]3 years ago

6 0

It's oxygen bc there's only 1 atom of it in a water molecule

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n the laboratory, a general chemistry student measured the pH of a 0.342 M aqueous solution of ethylamine, C2H5NH2 to be 12.067.

Tasya [4]

Answer:

The value of $K_b$ of the an ethylamine is $4.121\times 10^{-4}$ .

Explanation:

The pH of the solution = 12.067

The pOH of the solution = 14 - pH =14-12.607 =1.933

$pOH=-\log[OH^-]$

$1.933=-\log[OH^-]$

$[OH^-]=0.0117 M$

$C_2H_5NH_2+H_2O\rightleftharpoons C_2H_5NH_3^{+}+OH^-$

Initially

0.342 M 0 0

At equilibrium

(0.342-x) x x

The value of x = $[OH^-]=0.0117 M$

The expression of $K_b$ is given as:

$K_b=\frac{[C_2H_5NH_3^{+}][OH^-]}{[C_2H_5NH_2]}$

$K_b=\frac{x^2}{(0.342-x)}$

$K_b=\frac{(0.0117 )^2}{(0.342-0.0117)}=4.121\times 10^{-4}$

The value of $K_b$ of the an ethylamine is $4.121\times 10^{-4}$ .

7 0

3 years ago

Predict the initial and isolated products for the reaction. The starting material is a 6 carbon chain where there is a triple bo

satela [25.4K]

Answer:

See explanation and image attached

Explanation:

This reaction is known as mercuric ion catalyzed hydration of alkynes.

The first step in the reaction is attack of the mercuric ion on the carbon-carbon triple bond, a bridged intermediate is formed. This bridged intermediate is attacked by water molecule to give an organomercury enol. This undergoes keto-enol tautomerism, proton transfer to the keto group yields an oxonium ion, loss of the mercuric ion now gives equilibrium keto and enol forms of the compound. The keto form is favoured over the enol form.

7 0

3 years ago

What is the empirical formula of a compound composed of 30.5 g potassium (k) and 6.24 g oxygen (o)?

VLD [36.1K]

K5O2

convert grams to moles, divide both by the smallest mole mass, multiply that until hole.

30.5 g K ÷ 39.10 = .78 mol
6.24 g O ÷ 16 = .39 mol
.78 mol ÷ .39 mol = 2.5
.39 mol ÷ .39 mol = 1
2.5 x 2 = 5
1 x 2 = 2
K5O2

5 0

3 years ago

Which law was used to determine the relationship between the volume and the number of moles?

lawyer [7]

Answer:

The Mole-Volume Relationship: Avogadro's Law. A plot of the effect of temperature on the volume of a gas at constant pressure shows that the volume of a gas is directly proportional to the number of moles of that gas. This is stated as Avogadro's law.

Explanation:

4 0

3 years ago

According to Le Chatelier’s principle, a change in pressure affects the chemical equilibrium of the reaction system under what c

charle [14.2K]

Some of the reactants or the products are in the gaseous phase.

7 0

4 years ago

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