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pshichka [43]
3 years ago
11

What is the formula for triphosphorus tetrasulfide?

Chemistry
1 answer:
sladkih [1.3K]3 years ago
3 0

Answer:

P3S4

Explanation:

hope this helps

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Scientific theories are usually
jasenka [17]

Answer:

B

Explanation:

Cuz they are supported once discovered and then widely spread then accepted

4 0
4 years ago
Read 2 more answers
A welding torch produces a flame by burning acetylene fuel in the presence of oxygen. This flame is used to melt a metal. Which
NISA [10]

Answer:

chemical energy into thermal energy

Explanation:

The reaction taking place is as follows

2C₂H₂ + 5O₂ = 4CO₂ + 2H₂O + Heat

In this reaction bonds present in acetylene is broken and new bond present in water and carbon dioxide are formed . In the whole process of bond breaking and bond formation , there is net loss of energy and that energy is released as heat energy .

Thus we can say that in the whole process , chemical energy is converted into heat energy .

5 0
3 years ago
you record the sea temperature at 12 degrees North 45 degrees West to be 27.5 degrees Celcius the humidity to be very high and a
Cerrena [4.2K]
 For a hurricane to form, the sea temperature must be at least 26.7. The temperature of the water in the problem is 27.5. 
Another condition is that there should be little wind in the area. The problem states that there is a very light breeze. Finally, the humidity must be high.
Therefore, it is expected that a hurricane will form at the given location.
4 0
3 years ago
An aqueous magnesium chloride solution is made by dissolving 7.15 moles of MgCl2 in sufficient water so that the final volume of
irinina [24]

Answer:

2.86mol/L

Explanation:

Given parameters:

Number of moles of MgCl₂  = 7.15moles

Volume of solution  = 2.50L

Unknown:

Molarity of the MgCl₂ solution = ?

Solution:

The molarity of a solution is the number of moles of solute found in a given volume.

  Molarity  = \frac{number of moles }{volume}  

 Insert the parameters and solve;

   Molarity  = \frac{7.15}{2.5}   = 2.86mol/L

4 0
3 years ago
Pu is a nuclear waste byproduct with a half-life of 24,000 y. What fraction of the 239Pu present today will be present in 1000 y
olya-2409 [2.1K]

Answer:

0.9715 Fraction of Pu-239 will be remain after 1000 years.

Explanation:

\lambda =\frac{0.693}{t_{\frac{1}{2}}}

A=A_o\times e^{-\lambda t}

Where:

\lambda= decay constant

A_o =concentration left after time t

t_{\frac{1}{2}} = Half life of the sample

Half life of Pu-239 = t_{\frac{1}{2}}=24,000 y[

\lambda =\frac{0.693}{24,000 y}=2.8875\times 10^{-5} y^{-1]

Let us say amount present of  Pu-239 today = A_o=x

A = ?

A=x\times e^{-2.8875\times 10^{-5} y^{-1]\times 1000 y}

A=0.9715\times x

\frac{A}{A_0}=\frac{A}{x}=0.9715

0.9715 Fraction of Pu-239 will be remain after 1000 years.

7 0
3 years ago
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