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3 years ago

Explain the topic of velocity

Physics

2 answers:

jeka57 [31]3 years ago

7 0

Answer:

the speed of something in a given direction.

Explanation:

so basically. like when you're driving a car or riding in one the speed of which you are traveling is a type of velocity

Sholpan [36]3 years ago

3 0

Formula is inital position (0m) - final position (lets say 235m) divided by time(lets say 25 sec) (235-0)/25=9.4 so the velocity of the object was 9.4

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Investigator Robbins is called to the scene of a robbery. The officer on the scene thinks that the suspect entered the home from

ICE Princess25 [194]

Answer:

Explanation:

Since the evidence found points to the window on investigation remember there was a foot print below the window as well as the window been opened.

8 0

3 years ago

Force X has a magnitude of 1260 pounds, and Force Y has a magnitude of 1530 pounds. They act on a single point at an angle of 4

weeeeeb [17]

Answer:

Fe= 2579.68 P

α= 24.8°

Explanation:

Look at the attached graphic

we take the forces acting on the x-y plane and applied at the origin of coordinates

FX = 1260 P , horizontal (-x)

FY = 1530 P , forming 45° with positive x axis

x-y components FY

FYx= - 1530*cos(45)° = - 1081.87 P

FYy= - 1530*sin(45)° = - 1081.87 P

Calculation of the components of net force (Fn)

Fnx= FX + FYx

Fnx= -1260 P -1081.87 P

Fnx= -2341.87 P

Fny=FYy

Fny= -1081.87 P

Calculation of the components of equilibrant force (Fe)

the x-y components of the equilibrant force are equal in magnitude but in the opposite direction to the net force components:

Fnx= -2341.87 P, then, Fex= +2341.87 P

Fny= -1081.87 P P, then, Fex= +1081.87 P

Magnitude of the equilibrant (Fe)

$F_{n} = \sqrt{(F_{nx})^{2} +(F_{ny})^{2} }$

$F_{e} =\sqrt{(2341.87)^{2}+(1081.87)^{2} }$

Fe= 2579.68 P

Calculation of the direction of equilibrant force (α)

$\alpha =tan^{-1} (\frac{F_{ny} }{F_{nx} } )$

$\alpha =tan^{-1} (\frac{1081.87 }{2341.87} )$

α= 24.8°

Look at the attached graphic

6 0

3 years ago

A Van de Graaff generator is charged with 2.82 x 106C of positive charge.

Anvisha [2.4K]

B becuse that’s is right

3 0

3 years ago

Can someone Plzzz help meee.

mario62 [17]

solid...............

6 0

3 years ago

A rectangular block floats in pure water with 0.400 in. above the surface and 1.60 in. below the surface. When placed in an aque

labwork [276]

Answer:

specific gravity = 0.8

specific gravity of solution = 2

Explanation:

given data

rectangular block above water = 0.400 in

rectangular block below water = 1.60 in

material floats below water = 0.800 in

solution

first we get here specific gravity of block that is

specific gravity = block vol below ÷ total block vol × specific gravity water ..............1

put here value we get

specific gravity = $\frac{1.60}{1.60+0.400}$ × 1

specific gravity = 0.8

and now we get here specific gravity of solution that is express as

specific gravity of solution = total block vol ÷ block vol below × specific gravity block ........................2

put here value we get

specific gravity of solution = $\frac{1.60+0.400}{0.800}$ × 0.8

specific gravity of solution = 2

6 0

3 years ago