Answer:
22425 J
Explanation:
From the question,
Applying
Q = cm(t₂-t₁).................. Equation 1
Where Q = Thermal Energy, c = specific heat capacity of aluminium, m = mass of aluminium, t₂ = Final Temperature, t₁ = Initial Temperature.
Given: c = 897 J/kg.K, m = 1.0 kg, t₁ = 50 °C, t₂ = 25 °C (The final temperature is reduced by half)
Substitute these values into equation 1
Q = 897×1×(25-50)
Q = 897×(-25)
Q = -22425 J
Hence the thermal energy lost by the aluminium is 22425 J
Answer:
Established a government for the Northwest Territory, outlined the process for admitting a new state to the Union, and guaranteed that newly created states would be equal to the original thirteen states
Explanation:
Goooogle, so I hope this helps somewhat
Also, isn't this a History question? You put physics lol
Yes, it is diffusion !
Diffusion is the process in which gas, through random movement of particles, tends to fill up the whole volume of the container in which it is placed. So a similar process would lead the smoke, which is in form of gas (or light particles), to fill in the whole room in which it is contained.
Answer:
The electric force between them is 878.9 N
Explanation:
Given:
Identical charge
C
Separation between two charges
m
For finding the electrical force,
According to the coulomb's law

Here, force between two balloons are repulsive because both charges are same.
Where 

N
Therefore, the electric force between them is 878.9 N
Answer: 
Explanation:
Let's begin by explaining that the relation between the Celsius scale and Kelvin scale is:

This means the absolute zero point of the Kelvin scale is 
Keeping this in mind, we have the freezing point and boling point of Methane as:
Freezing point: 
Boiling point: 
According to this, there is a linear relation between the methane scale (
) and the Kelvin scale in the form:
(1)
Where:
is the temperature in Kelvin
is the temperature in degrees Methane
Firstly, we need to find the value of
and
with the two given points (
and
):
When
and
:

(2)
When
and
:

(3)
Now we have the linear equation:
(4)
Isolating
:
(5)
Evaluating for
:
(6)
Finally:
This means