3 years ago

What is the kinetic energy of a 0.012 kg bullet traveling at 700 m/s?

Physics

1 answer:

andriy [413]3 years ago

8 0

Answer:

m=0.012

v=700

KE = 1/2mv^2

KE = 1/2(700)(0.012)

KE = 4.2J

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