Answer:
f = 931.1 Hz
Explanation:
Given,
Mass of the wire, m = 0.325 g
Length of the stretch, L = 57.7 cm = 0.577 m
Tension in the wire, T = 650 N
Frequency for the first harmonic = ?
we know,

μ is the mass per unit length
μ = 0.325 x 10⁻³/ 0.577
μ = 0.563 x 10⁻³ Kg/m
now,

v = 1074.49 m/s
The wire is fixed at both ends. Nodes occur at fixed ends.
For First harmonic when there is a node at each end and the longest possible wavelength will have condition
λ=2 L
λ=2 x 0.577 = 1.154 m
we now,
v = f λ


f = 931.1 Hz
The frequency for first harmonic is equal to f = 931.1 Hz
here we know that the speed of the signal is same as the speed of light
so here we will have

the altitude of the airplane is given as

now we know that time taken by the signal to reach the control tower is given as

now it is given as


so above is the time taken by the signal to reach the control tower
The time of a wave is 65 m/sec. if the wavelength of the wave is 0.8 meters. what is the speed of this wave?
answer- the speed is 52
A conductor contains electrons that are bound so weakly to their atoms
that they can be ripped away with a small voltage, and sent scurrying in
the direction of the higher potential.