Frequency = (speed) / (wavelength)
Speed = 3 x 10⁸ m/s
Wavelength = 3 cm = 0.03 m
Frequency = (3 x 10⁸ m/s) / (0.03 m)
Frequency = (3 x 10⁸ / 0.03) (m / m-s)
Frequency = 1 x 10¹⁰ Hz (10 Gigahertz)
A)0
b)magnitude of the force on the car is 500n
Answer:
Total distance = 700 m
Displacement = 500 m
Explanation:
Notice that Jed travelled a total of 3 x 100 m = 300 m in the North direction, and 300 m + 100 m = 400 m in the East direction. Therefore the total distance he travelled is: 300 + 400 = 700 m.
But the actual displacement is given by the Pythagorean theorem as the hypotenuse of a right angle triangle of legs 300 m and 400 m:
displacement = 
Speed = 52/1.57576= 33 m/s
Explanation:
Distance = speed * time
Given , the distance traveled by the baseball = 52 m
Speed of sound in air = 330 m/s
Total time = 1.73333 s .
Total time for the student to hear the sound of the gong is the sum of the time take for the baseball to reach the gong and the time taken by the sound to travel back.
Distance traveled by the sound is 52 m and the speed is 330 m/s
So time taken by the sound to travel back = distance traveled / the speed
=> time = 52/330 s = 0.15757 s
Time taken by the base ball to reach the gong is the total time - the time taken by the sound
=> time taken by base ball = 1.73333 - 0.15757 = 1.57576s
Speed of the base ball to reach the gong = distance / time
Speed = 52/1.57576= 33 m/s
Answer:
1988 m
Explanation:
Range of a projectile
R = U²sin2∅/g...................... Equation 1
Where R = Range, U = Initial velocity, g = acceleration due to gravity, ∅ = Angle of projection.
Given: U = 150 m/s, ∅ = 60°
Constant: g = 9.8 m/s².
Substitute these values into equation 1
R = 150²(sin60°)/9.8
R = 22500(0.866)/9.8
R = 1988 m
Hence the Range of the projectile is 1988 m
