The units for G must be ![[N][m^2][kg^{-2}]](https://tex.z-dn.net/?f=%5BN%5D%5Bm%5E2%5D%5Bkg%5E%7B-2%7D%5D)
Explanation:
The magnitude of the gravitational force between two objects is given by:
where
F is the force
G is the gravitational constant
are the masses of the two objects
is the separation between the objects
We know that:
- The units of F are Newtons (N)
- The units of
are kilograms (kg) - The units of are metres (m)
So, we can rewrite the equation in terms of G, to find its units:
![G=\frac{Fr^2}{m_1 m_2}=\frac{[N][m]^2}{[kg][kg]}=[N][m^2][kg^{-2}]](https://tex.z-dn.net/?f=G%3D%5Cfrac%7BFr%5E2%7D%7Bm_1%20m_2%7D%3D%5Cfrac%7B%5BN%5D%5Bm%5D%5E2%7D%7B%5Bkg%5D%5Bkg%5D%7D%3D%5BN%5D%5Bm%5E2%5D%5Bkg%5E%7B-2%7D%5D)
Learn more about gravitational force:
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Efficiency = Work Output / Work Input
92% = Work Output / 100
0.92 = Work Output / 100
Work Output = 0.92 * 100
Work Output = 92 joules.
Answer:
.067 so C
Explanation:
I asked my sister who is in 2nd grade and she said it was right so you are good! =). have a great day!
Hello.
The gaseous state is the more compressible state, because it has the volume of its container.
The liquid state is virtually incompressible, and the solid state compression is very small.
The plasma is another state that has high compression, but in this case the matter is not bound(we don't have the proton in the core of the atom)
Answer:
Explanation:
The unknown charge can not remain in between the charge given because force on the middle charge will act in the same direction due to both the remaining charges.
So the unknown charge is somewhere on negative side of x axis . Its charge will be negative . Let it be - Q and let it be at distance - x on x axis.
force on it due to rest of the charges will be equal and opposite so
k3q Q / x² =k 8q Q / (L+x)²
8x² = 3 (L+x)²
2√2 x = √3 (L+x)
2√2 x - √3 x = √3 L
x(2√2 - √3 ) = √3 L
x = √3 L / (2√2 - √3 )
Let us consider the balancing force on 3q
force on it due to -Q and -8q will be equal
kQ . 3q / x² = k3q 8q / L²
Q = 8q (x² / L²)
so charge required = - 8q (x² / L²)
and its distance from x on negative x side = √3 L / (2√2 - √3 )
