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Xelga [282]
3 years ago
15

Technician A says a that a voltmeter can be used to monitor the output signal of an optical sensor. Technician B says that optic

al sensors should be tested with an oscilloscope because of the sensor's speed. Which technician is correct?
A. Technician A only
B. Technician B only
C. Both technicians A and B
D. Neither technician A nor B
Physics
1 answer:
katrin2010 [14]3 years ago
5 0

Answer:

B. Technician B only

Explanation:

An oscilloscope can be used to check the output signal of an optical sensor. The oscilloscope has the functioning of viewing the results in the form of waveform and its time scale settings can be altered to meet the requirements of the results.

A voltmeter cannot be <u>directly</u> used to monitor the output signal of an optical sensor. But a <u>digital multi-meter</u> can be used to check an optical sensor if the digital multi-meter is set on AC - Volt reading mode.

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What is due to acids formed when atmospheric and volcanic gases mix with water
Ilya [14]

Answer:

Acid rain results when sulfur dioxide (SO2) and nitrogen oxides (NOX) are emitted into the atmosphere and transported by wind and air currents. The SO2 and NOX react with water, oxygen, and other chemicals to form sulfuric and nitric acids. These then mix with water and other materials before falling to the ground.

Explanation:

5 0
3 years ago
A student wants to demonstrate entropy using the songs on her portable
Salsk061 [2.6K]

Answer:

Explanation:

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8 0
3 years ago
A horizontal vinyl record of mass 0.10 kg and radius 0.10 m rotates freely about a vertical axis through its center with an angu
Tresset [83]

Answer:

The angular speed of the record is 3.36 rad/s.

Explanation:

Given that,

Mass of record= 0.10 kg

Radius = 0.10 m

Angular speed = 4.7 rad/s

Moment of inertia I=5.0\times10^{-4}\ kgm^2

Mass of putty = 0.020 kg

We need to calculate the angular speed

Using law of conservation of momentum

L_{i}=L_{f}

I\omega_{i}=(I+mr^2)\omega_{f}

\omega_{f}=\dfrac{I\omega_{i}}{(I+mr^2)}

Put the value into the formula

\omega_{f}=\dfrac{5.0\times10^{-4}\times4.7}{5.0\times10^{-4}+0.020\times(0.10)^2}

\omega_{f}=3.36\ rad/s

Hence, The angular speed of the record is 3.36 rad/s.

3 0
3 years ago
Explain the differences between the geocentric theory of the universe and the heliocentric theory
Margarita [4]

Geocentric Theory

In astronomy, the geocentric model is a superseded description of the Universe with Earth at the center. Under the geocentric model, the Sun, Moon, stars, and planets all orbited Earth

Heliocentric Theory

Heliocentrism is the astronomical model in which the Earth and planets revolve around the Sun at the center of the Solar System. Historically, heliocentrism was opposed to geocentrism, which placed the Earth at the center

G-Theory is the earth is the center of the universe.

H-Theory is the sun is the center of the universe.

8 0
3 years ago
A bungee jumper of mass 75kg is attached to a bungee cord of length L=35m. She walks off a platform (with no initial speed), reac
attashe74 [19]

Answer:

1. 77.31 N/m

2. 26.2 m/s

3. increase

Explanation:

1. According to the law of energy conservation, when she jumps from the bridge to the point of maximum stretch, her potential energy would be converted to elastics energy. Her kinetic energy at both of those points are 0 as speed at those points are 0.

Let g = 9.8 m/s2. And the point where the bungee ropes are stretched to maximum be ground 0 for potential energy. We have the following energy conservation equation

E_P = E_E

mgh = kx^2/2

where m = 75 kg is the mass of the jumper, h = 72 m is the vertical height from the jumping point to the lowest point, k (N/m) is the spring constant and x = 72 - 35 = 37 m is the length that the cord is stretched

75*9.8*72 = 37^2k/2

k = (75*9.8*72*2)/37^2 = 77.31 N/m

2. At 35 m below the platform, the cord isn't stretched, so there isn't any elastics energy, only potential energy converted to kinetics energy. This time let's use the 35m point as ground 0 for potential energy

mv^2/2 = mgH

where H = 35m this time due to the height difference between the jumping point and the point 35m below the platform

v^2/2 = gH

v = \sqrt{2gH} = \sqrt{2*9.8*35} = 26.2 m/s

3. If she jumps from her platform with a velocity, then her starting kinetic energy is no longer 0. The energy conservation equation would then be

E_P + E_k = E_E

So the elastics energy would increase, which would lengthen the maximum displacement of the cord

5 0
4 years ago
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