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Nitella [24]
3 years ago
10

Help fast please!!!!!

Physics
2 answers:
Svet_ta [14]3 years ago
8 0

Answer:

the answer is A

Hope tis helps:)

Explanation:

inysia [295]3 years ago
6 0

We're told that the planets have EQUAL MASS.

If that's true, then the strength of the gravitational forces between
each planet and the star depends only on the distance between
them ... the farther a planet is from the star, the smaller the
gravitational forces are IF we're talking about planets with
equal masses.

Planet-X is closer to the star, and Planet-Y is farther from it. 
From this we know that the gravitational forces between the
star and Planet-X are greater, and the forces between the star
and Planet-Y are smaller.

'A' says this.

'B' is totally absurd, because it talks about gravity repelling things.

'C' says exactly the opposite for the two planets.

'D' says that distance doesn't matter.  We know this is absurd,
simply because we're never pulled toward Jupiter in our daily life.

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Answer:

it is B

Explanation:

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Does poop come out the pp or the butt please help im so confused best awnser gets brainleist
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A machine exerts a 100 N force to the right over a 5.00 meter length in 4.00 seconds. Calculate the power output of this machine
bixtya [17]

125 W is the power output of this machine.

Answer:

Explanation:

Power is defined as the amount of work done on the system to move that system from its original state within the given time interval. So it can be determined by the ratio of work done with time interval. As work done is the measure of force required to move a system to a certain distance. Work done is calculated as product of force with displacement.

So in the present case, the force is given as 100 N, the displacement is given as 5 m and the time is given as 4 s, then power is

Power = \frac{Work done}{Time}

As Work done = Force acting on the machine × Displacement

So Power = \frac{(Force * Displacement)}{Time}

Power = \frac{(100*5)}{4}=125 W

So, 125 W is the power output of this machine.

6 0
3 years ago
An object of height 2.4 cm is placed 29 cm in front of a diverging lens of focal length 19 cm. Behind the diverging lens, and 11
Arada [10]

Answer:

122.735 behind converging lens ; 2.16

Explanation:

Given tgat:

Object distance, u = 29 cm

Image distance, v =

Focal length, f = - 19 (diverging lens)

Mirror formula :

1/u + 1/v = 1/f

1/29 + 1/v = - 1/19

1/v = - 1/19 - 1/29

1/v = −0.087114

v = −11.47916

v = -11.48

Second lens

Object distance :

u = 11.48 + 11 = 22.48 cm

1/v = 1/19 - 1/22.48

1/v = 0.0081475

v = 1 / 0.0081475

v = 122.735 cm

122.735 behind second lens

Magnification, m

m = m1 * m2

m = - v / u

Lens1 :

m1 = -11.48 / 29 = - 0.3958620

m2 = - 122.735 / 22.48 = - 5.4597419

Hence,

- 0.3958620 * - 5.4597419 = 2.16

8 0
3 years ago
What is a hypothesis?
Maslowich
Is something you don't know so you guess before you do the experiment or project 
4 0
3 years ago
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