Answer:
<h2>C. </h2>
Explanation:
<h3>#CARRY ON LEARNING</h3><h3>#MARK ON LEARNING</h3><h3>#HELPING HAND</h3>
The distance of the airplane from the radar will be 1.08×10⁶ m. Distance can refer to a physical length.
<h3>What is distance?</h3>
Distance is a numerical representation of the distance between two objects or locations.
The distance of the airplane from the radar is found by the formula;
Distance = velocity × time
Distance = 3.0 x 10^8 m/s× 0.0036 s,
Distance = 1.08×10⁶ m.
Hence, the distance of the airplane from the radar will be 1.08×10⁶ m.
To learn more about the distance, refer to the link;
brainly.com/question/26711747
#SPJ1
Answer:
<em>0.25</em>
Explanation:
According to newtons law of motion
\sum F_x = ma
F_f = ma
nR = ma
nmg = ma
ng = a
n = a/g
g is the acceleration due to gravity
Given
a = 2.42m/s²
g = 9.8m/s²
Substitute into the formula;
n = 2.42/9.8
n = 0.25
<em>Hence the coefficient of kinetic friction is 0.25</em>
<em></em>
Answer:
(a) I (Moment of inertia)=0.0987 
(b) W(Angular Speed)=2.66 
Explanation:
Given data
m (Monkey mass)= 1.80 kg
d=2.50 m
T (Time Period)=0.940 s
Angle= 0.400 rad
(a) I (Moment of Inertia)=?
(b) W (Angular Speed)=?
For part (a) I (Moment of Inertia)=?
Time Period Formula is given as

After Simplifying we get



For Part (b) Angular Speed
From Kinetic Energy we get

Pontential Energy

KE=PE




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