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Vikki [24]
3 years ago
15

A vertical rectangular wall with a width of 20 m and a height of 12 m is holding a 7-m-deep water body. The resultant hydrostati

c force acting on this wall is (a) 1370 kN (b) 4807 kN (c) 8240 kN (d) 9740 kN (e) 11,670 kN
Physics
1 answer:
denis23 [38]3 years ago
5 0

Answer:

(c) 8240 kN

Resultant hydrostatic force F = 8240 kN

Explanation:

Force can be expressed as;

F = ma

F = mg ......1

Where,

F = force

m = mass

a = acceleration

g = acceleration due to gravity

And we know that mass of an object is the product of

Density and Volume

m = pV

And volume V = area × height = Ah

m = pAh .....2

Substituting m into equation 1

F = pAhg = pghA ......3

Given;

Density of water p = 1000kg/m^3

g = 9.81m/s^2

Area A = 20m × 12m = 240m^2

h = depth/2 = 7/2 = 3.5m

Substituting the values into equation 3, we have;

F = 1000×9.81×3.5×240

F = 8240400 N

Resultant hydrostatic force F = 8240 kN

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A spring hangs from the ceiling with an unstretched length of x 0 = 0.69 m x0=0.69 m . A m 1 = 7.5 kg m1=7.5 kg block is hung fr
sergejj [24]

Answer:

x2=0.732m

Explanation:

We can calculate the spring constant using the equilibrium equation of the block m1. Since the spring is in equilibrium, we can say that the acceleration of the block is equal to zero. So, its equilibrium equation is:

m_1g-k\Delta x_1=0\\\\\implies k=\frac{m_1g}{\Delta x_1}\\\\k=\frac{(7.5kg)(9.8m/s^{2})}{0.84m-0.69m}=490N/m

Then using the equilibrium equation of the block m2, we have:

m_2g-k\Delta x_2=0\\\\\\implies x_2=x_0+\frac{m_2g}{k} \\x_2=0.69m+\frac{(2.1kg)(9.8m/s^{2})}{490N/m}= 0.732m

In words, the lenght x2 of the spring when the m2 block is hung from it, is 0.732m.

6 0
3 years ago
One strategy in a snowball fight is to throw a snowball at a high angle over level ground. Then, while your opponent is watching
agasfer [191]

Answer:

  22.5°

Explanation:

<u>Short answer</u>: The trajectories will hit the same target when the projectile is launched at complementary angles. The second angle is 90° -67.5° = 22.5°.

__

<u>Longer answer</u>: The horizontal speed of the snowball launched at angle α with speed s is ...

  vh = s·cos(α)

Then the horizontal distance at time t is ...

  x = vh·t

and the time taken to get to some distance x is ...

  t = x/vh = x/(s·cos(α))

The equation for the vertical motion of the projectile is ...

  y = -4.9t² +s·sin(α)·t

Substituting the above expression for t, we have y in terms of x:

  y = -4.9x²/(s·cos(α))² +(s·sin(α)·x)/(s·cos(α))

Factoring gives ...

  y = (x/(cos(α))(-4.9x/(s²·cos(α)) +sin(α))

The height y will be zero at x=0 and at ...

  0 = -4.9x/(s²·cos(α)) +sin(α)

  x = s²·sin(α)·cos(α)/4.9 = (s²/9.8)sin(2α)

So, for some alternate angle β, we want ...

  sin(2α) = sin(2β)

We know this will be the case for ...

  2β = 180° -2α

  β = 90° -α

The second snowball should be thrown at an angle of 90°-67.5° = 22.5° to make it hit the same point as the first.

3 0
3 years ago
Science Tolliver
Nookie1986 [14]

Answer:

Objects; waves.

Explanation:

Waves interact with objects and other waves. Thus, waves are used on objects such as mobile phones and can be transformed from one form to another.

There are various types of waves in our physical environment such as gamma rays, x-rays, ultraviolet waves, radio waves etc.

Radio waves can be defined as an electromagnetic wave that has its frequency ranging from 30 GHz to 300 GHz and its wavelength between 1mm and 3000m. Therefore, radio waves are a series of repetitive valleys and peaks that are typically characterized of having the longest wavelength in the electromagnetic spectrum.

Basically, as a result of radio waves having long wavelengths, they are mainly used in long-distance communications such as the carriage and transmission of data. Some examples of communication technologies that uses radio waves are radio set, mobile phones, television etc.

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It is letter b which is Global Warming
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