Answer:
470 N.
Explanation:
Using equations of motion:
S = vi*t + 1/2*(a*(t^2))
Given:
S = 0.65 m
t = 1.5 s
vi = 0 m/s
0.65 = 1/2 * (a * (1.5)^2)
a = 1.3/2.25
= 0.578 m/s^2
Force = mass * acceleration due to gravity
= 92 * 0.578
= 53.16 N
Total force = 420 + 53.16
= 473.16 N
= 470 N.
Decompose the forces acting on the block into components that are parallel and perpendicular to the ramp. (See attached free body diagram. Forces are not drawn to scale)
• The net force in the parallel direction is
∑ <em>F</em> (para) = -<em>mg</em> sin(21°) - <em>f</em> = <em>ma</em>
• The net force in the perpendicular direction is
∑ <em>F</em> (perp) = <em>n</em> - <em>mg</em> cos(21°) = 0
Solving the second equation for <em>n</em> gives
<em>n</em> = <em>mg</em> cos(21°)
<em>n</em> = (0.200 kg) (9.80 m/s²) cos(21°)
<em>n</em> ≈ 1.83 N
Then the magnitude of friction is
<em>f</em> = <em>µn</em>
<em>f</em> = 0.25 (1.83 N)
<em>f</em> ≈ 0.457 N
Solve for the acceleration <em>a</em> :
-<em>mg</em> sin(21°) - <em>f</em> = <em>ma</em>
<em>a</em> = (-0.457N - (0.200 kg) (9.80 m/s²) sin(21°))/(0.200 kg)
<em>a</em> ≈ -5.80 m/s²
so the block is decelerating with magnitude
<em>a</em> = 5.80 m/s²
down the ramp.
<span>None of the light passes through it; some of the light is absorbed as heat but most is reflected off the surface. This is how you see </span>objects. reflected light from them hits your eye. (Opaque means not transparent)
The initial velocity of the stone is 0 ft/s. Given the initial velocity (Vi), final velocity (Vf), and acceleration due to gravity (g), the distance may be calculated through the equation,
d = ((Vf)² - (Vi)²) / 2g
Substituting the known values,
d = ((96 ft/s)² - 0))/ (2x32.2)
The value of d is 143.10 ft.
Answer: The bond that hold water molecules together are due to shared electrons. The bond of shared electrons is known as a covalent bond.
Explanation: Water is held together by bonds known as covalent bonds, in which electrons are shared by the elements. In this case, the two hydrogen atoms and the one oxygen atom share a bond in which they share electrons, attaining a full outer shell.