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goldenfox [79]
3 years ago
12

.....................

Mathematics
1 answer:
iris [78.8K]3 years ago
3 0
I believe the answer you are looking for is 4^15. I'm not 100% sure though. 
Hope it helps!
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The expression has exactly 2 terms terms true or false 7f + 15 - 2g
Dvinal [7]

In this case, the answer is very simple.

A term is a part not separated by the signs + or - .

In this expression, we have 3 terms.

The answer is: false.

3 0
1 year ago
Determine the x-intercept(s) of the rational function: <br> f(x) = (x ^ 2 - 16)/(x ^ 2 - 2x - 3)
elena55 [62]

Answer:

(-4,0) and (4,0)

Step-by-step explanation:

The x-intercepts occur for values of x where f(x) = 0.

f(x) = 0 when the nominator (x^{2}  - 16) = 0.

x^{2} -16 is a difference of squares,
so you can factor it as (x + 4)(x – 4)

When x = –4 or x = 4, the nominator is 0, and f(x) = 0

3 0
2 years ago
Solve the equation. 4(x − 7) − 128 = 9x − 5(x + 6)
vichka [17]

The equation 4(x − 7) − 128 = 9x − 5(x + 6) has no solution

<h3><u>Solution:</u></h3>

Given that 4(x − 7) − 128 = 9x − 5(x + 6)

We have to find the solution for this equation

4(x − 7) − 128 = 9x − 5(x + 6)

Let us use BODMAS rule to perform the sequence of operations

According to Bodmas rule, if an expression contains brackets ((), {}, []) we have to first solve or simplify the bracket followed by of (powers and roots etc.), then division, multiplication, addition and subtraction from left to right.

So let us solve for brackets first

4x - 28 - 128 = 9x - 5x - 30

Now let us perform subtraction

4x - 156 = 4x - 30

Now move the terms from R.H.S to L.H.S

4x - 4x = -30 + 156

0 \neq 126

Since there is no value of x that will ever make this a true statement, the solution to the equation above is “no solution”

So this equation has no solution

4 0
4 years ago
How do you solve: f(x) = -x2e-x<br> +2xe-x , finding the zero's of f.
Maksim231197 [3]

Answer:

0 and 2

Step-by-step explanation:

f(x) = -x^2e^{-x}+2xe^{-x}

To find zeros set f(x)=0  and solve for x

0 = -x^2e^{-x}+2xe^{-x}

0 = -e^{-x}(x^2-2x)

now factor out x

0 = -xe^{-x}(x-2)

set each factor =0 and solve for x

x=0

-e^{-x}=0 no solution for x

x-2=0, x=2

zeros of f  are 0 and 2

7 0
4 years ago
Topic 9 Review
Lesechka [4]
Merry Christmas and a happy new year
3 0
3 years ago
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