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3 years ago

If a guitar string vibrates at 304hz as its fundamental frequency, what is the frequency of the third harmonic?

Physics

1 answer:

Minchanka [31]3 years ago

6 0

Answer:

912 Hz

Explanation:

Third harmonic multiplies the frequency by 3. Harmonics are waves that operate at a frequency that is an integer (whole-number) multiple of the fundamental frequency.

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A roofer needs to get shingles onto a roof. Pulling the shingles up manually uses 1,549 N or force. The roofer decides to use a

joja [24]

Answer:

Mechanical advantage of pulleys = 3.47 (Approx)

Explanation:

Given:

Manual force = 1,549 N

Pulleys force = 446 N

Find:

Mechanical advantage of pulleys

Computation:

Mechanical advantage of pulleys = Manual force / Pulleys force

Mechanical advantage of pulleys = 1,549 / 446

Mechanical advantage of pulleys = 3.4730

Mechanical advantage of pulleys = 3.47 (Approx)

3 0

4 years ago

Many particles, such as dust, are inhaled when people breathe. Which part of the respiratory system filters out the majority of

sergey [27]

Answer:

A: Nose

Explanation:

Because your nose has mucus covered hairs that catch some of the dust particles that you inhale.

8 0

4 years ago

A 3.00 × 10^-6 kg ant rides the second hand of an enormous vertical wall clock. The ant smoothly sweeps a circle of radius 50.0

kotykmax [81]

Answer:

1.65×10⁻⁶ N

Explanation:

m = Mass of ant = $3\times 10^{-6}\ kg$

r = Radius = 50 m

t = Time taken to complete on rotation = 60 seconds

Angular velocity

$\omega=\frac{2\pi}{t}\\\Rightarrow \omega=\frac{2\pi}{60}$

Centripetal acceleration is force that is acting outward

$F_c=m\omega^2r\\\Rightarrow F_c=3\times 10^{-6}\times \left(\frac{2\pi}{60}\right)^2\times 50\\\Rightarrow F_c=1.65\times 10^{-6}\ N$

The magnitude of the upward force felt by the ant due to the second hand would be 1.65×10⁻⁶ N

4 0

3 years ago

You are using a Geiger counter to measure the activity of a radioactive substance over the course of several minutes. If the rea

KonstantinChe [14]

Answer : The half-life of this substance will be, 45 minutes.

Explanation :

First we have to calculate the value of rate constant.

Expression for rate law for first order kinetics is given by:

$k=\frac{2.303}{t}\log\frac{a}{a-x}$

where,

k = rate constant = ?

t = time passed by the sample = 90.3 min

a = initial amount of the reactant = 400

a - x = amount left after decay process = 100

Now put all the given values in above equation, we get

$k=\frac{2.303}{90.3min}\log\frac{400}{100}$

$k=1.54\times 10^{-2}\text{ min}^{-1}$

Now we have to calculate the half-life of substance, we use the formula :

$k=\frac{0.693}{t_{1/2}}$

$1.54\times 10^{-2}\text{ min}^{-1}=\frac{0.693}{t_{1/2}}$

$t_{1/2}=45min$

Therefore, the half-life of this substance will be, 45 minutes.

4 0

3 years ago

Physics is my answer correct?

Digiron [165]

Explanation:

zero..................

6 0

3 years ago

Read 2 more answers