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3 years ago

14

f you were trying to build a soundproof room, which of the following materials would you choose in order to absorb the most soun

d, based on the coefficient of absorption for each material? A. Wood B. Carpet C. Concrete D. Heavy curtains

1 answer:

musickatia [10]3 years ago

5 0

If you don't have the coefficient of absorption, I would say Heavy curtains.

Hope this helps :)

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A 55 kg person falling with a velocity of 0.6

siniylev [52]

Answer:

What are we supposed to find, if it is kinetic energy then this is the solution.

K.E=1/2mv^2

K.E= kinetic energy

M=mass

V=velocity

K.E =0.5*55*0.6^2

K.E=9.9J

Explanation:

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2 years ago

one group of atoms on the periodic tables are known as "noble gases". why have they been given this name?

maria [59]

This group is called “noble gases” because they do not react with other elements. This is because they have a full valence shell.

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3 years ago

does the wavelength of the sound increase, decrease, or stay the smae as the musician changes from the first sound to the second

Naya [18.7K]

Decrease K k kk kk k k k

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3 years ago

Read 2 more answers

A copper atom has an atomic number of 29 and an atomic mass of 64. What

Elina [12.6K]

Explanation:

Answer is B.

B. It has a central nucleus composed of 29 protons and 35 neutrons,surrounded by an electron cloud containing 29 electrons.

I hope it's helpful!

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2 years ago

In an inkjet printer, letters and images are created by squirting drops of ink horizontally at a sheet of paper from a rapidly m

Serga [27]

Answer:

$q = 6.48 \times 10^{-14} C$

Explanation:

Deflection in the drop is due to electric field force

so we will have

$F = qE$

acceleration of the drop is given as

$a = \frac{qE}{m}$

$a = \frac{q(7.75 \times 10^4)}{1.00 \times 10^{-11}}$

$a = 7.75 \times 10^{15} q$

now we know that time to cross the plates is given as

$t = \frac{D}{v}$

$t = \frac{0.02}{18}$

$t = 1.11 \times 10^{-3} s$

now the deflection is given as

$d = \frac{1}{2}at^2$

$0.310 \times 10^{-3} = \frac{1}{2}(7.75 \times 10^{15} q)(1.11 \times 10^{-3})^2$

$0.310 \times 10^{-3} = 4.78 \times 10^9 q$

$q = 6.48 \times 10^{-14} C$

5 0

3 years ago