The new current will be 4I. The power dissipated by the resistor will increase by a factor of 16.
<h3>What is a resistor?</h3>
- Using electrical resistance as a circuit element, a resistor is a passive electrical component with two terminals. In electrical circuits, resistors are used, among other things, to limit current flow, modify signal levels, divide voltages, bias active devices, and terminate transmission lines.
- As test loads for generators, power distribution systems, and motor controls, high-power resistors that can create many watts of heat rather than just electrical energy can be used.
- Variable resistors can be used as sensors for force, heat, light, humidity, humidity, and chemical activity or for adjusting circuit components.
- Electrical networks and electronic circuits frequently contain resistors, which are found everywhere in electronic equipment. Practical resistors are discrete components that come in a wide range of materials and forms.
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Answer:
The distance the train travels before coming to a (complete) stop = 40/81 km which is approximately 493.83 meters
Explanation:
The initial speed of the train u = 80 km/h = 22 2/9 m/s = 22.
m/s
The magnitude of the constant acceleration with which the train slows, a = 0.5 m/s²
Therefore, we have the following suitable kinematic equation of motion;
v² = u² - 2 × a × s
Where;
v = The final velocity = 0 (The train comes to a stop)
s = The distance the train travels before coming to a stop
Substituting the values gives;
0² = 22.
² - 2 × 0.5 × s
2 × 0.5 × s = 22.
²
s = 22.
²/1 = 493 67/81 m = 40/81 km
The distance the train travels before coming to a (complete) stop = 40/81 km ≈ 493.83 m.
Answer:
a = 12 [m/s²]
Explanation:
To solve this problem we must use Newton's second law which tells us that the sum of forces on a body is equal to the product of mass by acceleration.
ΣF = m*a
where:
ΣF = sum of forces acting on a body [N] (units of Newtons)
m = mass = 0.5 [kg]
a = acceleration [m/s²]
Let's take the direction of positive forces to the right and negative forces directed to the left
2 + 8 - 4 = 0.5*a
6 = 0.5*a
a = 12 [m/s²]
In calculating the energy of a photon of light, we need the relationship for energy and the frequency which is expressed as:
E=hv
where h is the Planck's constant (6.626 x 10-34 J s)and v is the frequency.
E = 6.626 x 10-34 J s (<span>7.33 x 10^14 /s) = 4.857 x 10^-19 J</span>
Answer:
14 m/s
Explanation:
The motion of the book is a free fall motion, so it is an uniformly accelerated motion with constant acceleration g=9.8 m/s^2 towards the ground. Therefore we can find the final velocity by using the equation:

where
u = 0 is the initial speed
g = 9.8 m/s^2 is the acceleration
d = 10.0 m is the distance covered by the book
Substituting data, we find
