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3 years ago

Theweight ofof body is 420N .Calculate its mass

Physics

1 answer:

Nady [450]3 years ago

6 0

Answer:

42.87

Explanation:

Google

OR

420/9.8 which equals 42.87.

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On a smooth horizontal floor an object

lukranit [14]

Answer:

what do you mean by this?

Explanation:

7 0

2 years ago

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An object is originally moving at a constant velocity of 8 m/s in the -x direction. It moves at this constant velocity for 3 sec

aivan3 [116]

Answer:

244.64m

Explanation:

First, we find the distance traveled with constant velocity. It's simply multiplying velocity time the time that elapsed:

$x = V*t = -8\frac{m}{s} *3s = -24m$

After this, the ball will start traveling with a constant acceleration motion. Due to the fact that the acceleration is the opposite direction to the initial velocity, this motion will have 2 phases:

1. The velocity will start to decrease untill it reaches 0m/s.

2. Then, the velocity will start to increase at the rate of the acceleration.

The distance that the ball travels in the first phase can be found with the following expression:

$v^2 = v_0^2 + 2a*d$

Where v is the final velocity (0m/s), v_0 is the initial velocity (-8m/s) and a is the acceleration (+9m/s^2). We solve for d:

$d = \frac{v^2 - v_0^2}{2a} = \frac{(0m/s)^2 - (-8m/s)^2}{2*7m/s^2}= -4.57m$

Now, before finding the distance traveled in the second phase, we need to find the time that took for the velocity to reach 0:

$t_1 = \frac{v}{a} = \frac{8m/s}{7m/s^2} = 1.143 s$

Then, the time of the second phase will be:

$t_2 = 9s - t_1 = 9s - 1.143s = 7.857s$

Using this, we using the equations for constant acceleration motion in order to calculate the distance traveled in the second phase:

$x = \frac{1}{2}a*t^2 + v_0*t + x_0$

V_0, the initial velocity of the second phase, will be 0 as previously mentioned. X_0, the initial position, will be 0, for simplicity:

$x = \frac{1}{2}*7\frac{m}{s^2}*t^2 + 0m/s*t + 0m = 216.07m$

So, the total distance covered by this object in meters will be the sum of all the distances we found:

$x_total = 24m + 4.57m + 216.07m = 244.64m$

8 0

2 years ago

5–111. A box having a weight of 8 lb is moving around in a circle of radius rA = 2 ft with a speed of (vA)1 = 5 ft>s while co

Elis [28]

Answer:

a) vB = 10.77 ft/s

b) W = 11.30 lb*ft

Explanation:

a) W = 8 lb ⇒ m = W/g = 8 lb/32.2 ft/s² = 0.2484 slug

vA lin = 5 ft/s

rA = 2 ft

v rad = 4 ft/s

vB = ?

rB = 1 ft

W = ?

We can apply The law of conservation of angular momentum

Lin = Lfin

m*vA*rA = m*vB*rB ⇒ vB = vA*rA / rB

⇒ vB = (5 ft/s)*(2 ft) / (1 ft) = 10 ft/s (tangential speed)

then we get

vB = √(vB tang² + vB rad²) ⇒ vB = √((10 ft/s)² + (4 ft/s)²)

⇒ vB = 10.77 ft/s

b) W = ΔK = KB - KA = 0.5*m*vB² - 0.5*m*vA²

⇒ W = 0.5*m*(vB² - vA²) = 0.5*0.2484 slug*((10.77 ft/s)²-(5 ft/s)²)

⇒ W = 11.30 lb*ft

6 0

2 years ago

PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!

Helga [31]

The third hour was positive acceleration and the second hour was negative acceleration

7 0

3 years ago

What is the mechanical advantage of a pulley system that uses 280 N to lift a 320 Kg box 4.0 m in the air?

SVEN [57.7K]

the force of effort is given as

E = effort force = 280 N

m = mass of box to be lifted = 320 kg

g = acceleration due to gravity = 9.8 m/s²

force of load due to weight of box is given as

L = force of load = mg

L = 320 x 9.8

L = 3136 N

mechanical advantage for pulley system is the simply the ratio of the effort put in to the load being lifted.

mechanical advantage is given as

MA = load/effort

MA = L/E

MA = 3136/280

MA = 11.2

6 0

2 years ago

Theweight ofof body is 420N .Calculate its mass​

Theweight ofof body is 420N .Calculate its mass