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elena55 [62]
3 years ago
11

Five different students in Mr. Garcia's class have done an experiment once, and each one got similar results. What should the st

udents do to increase the validity of their results?
Physics
2 answers:
trapecia [35]3 years ago
7 0

Repeat the experiment

Explanation:

To increase the validity of the results obtained from the single experiment, the students should be encouraged to repeat the experiments more number of times as much as possible.

In an experiment, scientist always try to limit errors by making precise and accurate observation.  A single observation does not really represent a precise and accurate finding. When an experiment is repeated as often as possible, the reliability of the conclusion drawn from the hypothesis testing will improve and the results can be accepted to be valid.

A single observation/experiment is not valid enough.

Learn more:

Experiments brainly.com/question/5096428

#learnwithBrainly

grandymaker [24]3 years ago
5 0

<em>Answer:</em>

<em>To increase the validity of the results, all the students of Mr. Gracia's class must perform a few more experimental trials.</em>

<em>Answer:  A</em>

<em>Explanation:</em>

<em>While dealing with the scientific analysis, one must always commit number of experiments to gain the most accurate and valid result. By doing number of trials, we get different approximate values that can be used to estimate the average result.</em>

<em>This average will be the nearest value of the exact answer if we add more and more number of experiments or trials. Since, the results are similar for each student in the class, they all should attempt more trials or experiments to get the most accurate result.</em>

<em />

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Please Help Me!
balandron [24]

The image distance when a boy holds a toy soldier in front of a concave mirror, with a focal length of 0.45 m. is -0.56 m.

<h3>What is image distance?</h3>

This is the distance between the image formed and the focus when an object is placed in front of a plane mirror.

To calculate the image distance, we use the formula below.

Formula:

  • 1/f = 1/u+1/v........... Equation 1

Where:

  • f = Focal length of the mirror
  • v = Image distance
  • u = object distance

From the question,

Given:

  • f = 0.45 m
  • u = 0.25 m

Substitute these values into equation 1 and solve for the image distance

  • 1/0.45 = 1/0.25 + 1/v
  • 2.22 = 4+1/v
  • 1/v = 2.22-4
  • 1/v = -1.78
  • v = 1/(-1.78)
  • v = -0.56 m

Hence, The image distance is -0.56 m.

Learn more about image distance here: brainly.com/question/17273444

5 0
1 year ago
Calculate the amount of air in a room 6m long, 5m wide and 3mm high.​
sattari [20]

Answer:

0.09kg of air

Explanation:

The dimensions of the room are given

change the height to meters by dividing it by thousand.

For the volume multiplying the length,width and height (all should be in the same unit most suitable being meters).

Volume refers to the amount of space inside a box or a object.

The amount of air is equal to the volume.

6 0
2 years ago
Read 2 more answers
If you are given force and time, you can determine power if you can know watts energy joules distance
shepuryov [24]

Answer:

distance

Explanation:

Distance is the missing quantity. It is needed to estimate the amount of work done by a force, and afterwards it is used to estimate the power, which is the work done over the time it took to complete it.

8 0
3 years ago
Read 2 more answers
About how much time elapses between high tides on the same day?
Pani-rosa [81]
There is about 12 hours
6 0
3 years ago
The average velocity of blood flowing in a certain 4-mm-diameter artery in the human body is 0.28 m/s. The viscosity and density
OLga [1]

Answer:

V = 3.5 x 10⁻⁶ m³/s = 3.5 cm³/s

Explanation:

The volume flow rate of the blood in the artery can be given by the following formula:

V = Av

where,

V = Volume flow rate = ?

A = cross-sectional area of artery = πd²/4 = π(0.004 m)²/4 = 1.26 x 10⁻⁵ m²

v = velcoity = 0.28 m/s

Therefore,

V = (1.26\ x\ 10^{-5}\ m^2)(0.28\ m/s)

<u>V = 3.5 x 10⁻⁶ m³/s = 3.5 cm³/s</u>

4 0
2 years ago
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