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elena55 [62]
3 years ago
11

Five different students in Mr. Garcia's class have done an experiment once, and each one got similar results. What should the st

udents do to increase the validity of their results?
Physics
2 answers:
trapecia [35]3 years ago
7 0

Repeat the experiment

Explanation:

To increase the validity of the results obtained from the single experiment, the students should be encouraged to repeat the experiments more number of times as much as possible.

In an experiment, scientist always try to limit errors by making precise and accurate observation.  A single observation does not really represent a precise and accurate finding. When an experiment is repeated as often as possible, the reliability of the conclusion drawn from the hypothesis testing will improve and the results can be accepted to be valid.

A single observation/experiment is not valid enough.

Learn more:

Experiments brainly.com/question/5096428

#learnwithBrainly

grandymaker [24]3 years ago
5 0

<em>Answer:</em>

<em>To increase the validity of the results, all the students of Mr. Gracia's class must perform a few more experimental trials.</em>

<em>Answer:  A</em>

<em>Explanation:</em>

<em>While dealing with the scientific analysis, one must always commit number of experiments to gain the most accurate and valid result. By doing number of trials, we get different approximate values that can be used to estimate the average result.</em>

<em>This average will be the nearest value of the exact answer if we add more and more number of experiments or trials. Since, the results are similar for each student in the class, they all should attempt more trials or experiments to get the most accurate result.</em>

<em />

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The regions of the Moon that are of higher elevation are known as the __________. These regions have a high albedo and display a
REY [17]

Answer:

lunar highlands

Explanation:

Seeing the moon from the earth we can see that some parts are more illuminated than others, these different regions of the moon have been assigned a name , and have different properties.

The brightest parts are called lunar highlands, because they are at a higher elevation than the darkest parts, called lunar marias.

The lunar highlands are seen from the earth a <u>whiter color than the rest of the moon</u> due to its altitude.

4 0
4 years ago
You are the captain of a pirate ship and wish to find out how strong a new first mate is at rowing treasure from shore to the sh
Kryger [21]
The formula that is usually used for the calculation of power is the product of force applied and the speed at which the action is done. That is,
                                     P = Fv
We let d be the distance covered and the equation for power would be,
                                     P = (500 N)(d/240 s)
                                     P = 2.08d
3 0
3 years ago
The legs of a weight lifter must ultimately support the weights he has lifted. A human tibia (shinbone) has a circular cross sec
Sergio039 [100]

Answer:

249003822308.05008 N

Explanation:

F = Force

\sigma = Breaking stress of bone = 150 MPa

d_2 = Outer diameter = 3.6 cm

d_1 = Inner diameter = 2.3 cm

Area of the bone is assumed to be a hollow cylinder

A=\dfrac{\pi}{4}(d_2^2-d_1^2)

Stress is given by

\sigma=\dfrac{F}{A}\\\Rightarrow F=\sigma A\\\Rightarrow F=\dfrac{150\times 10^6}{\dfrac{\pi}{4}(0.036^2-0.023^2)}\\\Rightarrow F=249003822308.05008\ N

The maximum weight the person can lift without breaking his legs is 249003822308.05008 N

3 0
4 years ago
Two long straight wires enter a room through a window. One carries a current of 3.0 ???? into the room while the other carries a
Tju [1.3M]

Answer:

\begin{equation}\\\oint_LB.dl\\\end{equation} = -8πx10^{-7}

Explanation:

If you need calculate

\begin{equation}\\\oint_L B.dl\\ \end{equation}

You can use the Ampere's Law

\begin{equation}\\\oint_L B.dl\\ \end{equation} = I_{in}μ

   

      Where I_{in}: Current passing through the window

                   μ : Free space’s magnetic permeability

                   μ = 4πx10^{-7} T.m.A^{-1}

Then

\begin{equation}\\\oint_L B.dl\\ \end{equation} = (3-5)4πx10^{-7}

\begin{equation}\\\oint_L B.dl\\ \end{equation} = -8πx10^{-7}

5 0
3 years ago
How can i find the acceleration?(rope and grinder have no weight) *** sorry for my english
Finger [1]
The main formula to be used here is

                       Force = (mass) x (acceleration).

We'll get to work in just a second.  But first, I must confess to you that I see
two things happening here, and I only know how to handle one of them.  So
my answer will be incomplete, but I believe it will be more reliable than the
first answer that was previously offered here.

On the <u>right</u> side ... where the 2 kg and the 3 kg are hanging over the same
pulley, those weights are not balanced, so the 3 kg will pull the 2kg down, with
some acceleration.  I don't know what to do with that, because . . .

At the <em>same time</em>, both of those will be pulled <u>up</u> by the 10 kg on the other side
of the upper pulley.

I think I can handle the 10 kg, and work out the acceleration that IT has.

Let's look at only the forces on the 10 kg:

-- The force of gravity is pulling it down, with the whatever the weight of 10 kg is.

-- At the same time, the rope is pulling it UP, with whatever the weight of 5 kg is ...
that's the weight of the two smaller blocks on the other end of the rope. 

So, the net force on the 10 kg is the weight of (10 - 5) = 5 kg, downward.

The weight of 5 kg is (mass) x (gravity) = (5 x 9.8) = 49 newtons.

The acceleration of 10 kg, with 49 newtons of force on it, is

     Acceleration = (force) / (mass) = 49/10 = <em>4.9 meters per second²</em>
7 0
3 years ago
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