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2 years ago

A dart player throws a dart horizontally at a velocity of 12.7 m/s. The

Physics

1 answer:

Igoryamba2 years ago

3 0

Answer:

Answer

Explanation:

It is given that,

The horizontal speed of a dart player =

12.4 m/s

The dart hits the board 0.32 m below the

height from which it was thrown.

We need to find how long it take the dart

to hit the board.

Let the time taken by the dart to hit the

board. Using second equation of motion

to find it.

y = ut +

at2

Put u = 0 and a=-g

-1

y =

1942

-0.32

x 9.8t2

2 x 0.32-0.32

9.8

t= 0.255 s

Let x be the horizontal distance travelled.

It is calculated as follows:

X =

12.4 x 0.255

= 3.16 m

So, the dart will hit the board at a

distance of 3.16 m.

Muscardinus • Quality

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A 40kg rock falls off a cliff that is 50 meters high. How fast is the speed of the rock when it hits the ground

Oksi-84 [34.3K]

31.3m/s

Explanation:

Given parameters:

Mass of rock = 40kg

Height of cliff = 50m

Unknown:

Speed of rock when it hits ground = ?

Solution:

We are going to use the appropriate motion equation to solve this problem

The rock is falling with the aid of gravitational force. The force is causing it to accelerate with an amount of velocity.

Using;

V² = U² + 2gH

V = unknown velocity

U = initial velocity = O

g = acceleration due to gravity = 9.8m/s²

H = height of fall

since the initial velocity of the bodyg is 0

V² = 2gH

V= √2gH = √2 x 9.8 x 50 = 31.3m/s

learn more:

Velocity brainly.com/question/4460262

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7 0

3 years ago

An electrically neutral model airplane is flying in a horizontal circle on a 2.0-m guideline, which is nearly parallel to the gr

amm1812

Answer:

q=3.5*10^-4

Explanation:

concept:

The force acting on both charges is given by the coulomb law:

F=kq1q2/r^2

the centripetal force is given by:

Fc=mv^2/r

The kinetic energy is given by:

KE=1/2mv^2

The tension force:

when the plane is uncharged

T=mv^2/r

T=2(K.E)/r

T=2(50 J)/r

T=100/r

when the plane is charged

T+k*|q|^2/r^2=2(K.E)charged/r

100/r+k*|q|^2/r^2=2(53.5 J)/r

q=√(2r[53.5 J-50 J]/k) √= square root on whole

q=√2(2)(53.5 J-50 J)/8.99*10^9

q=3.5*10^-4

5 0

2 years ago

If the distance from a light source triples, how does light intensity change? The intensity will be 3x greater. The intensity wi

Tcecarenko [31]

Answer:

The intensity will be 1/9 as much.

Explanation:

The intensity of the light or any source is inversely related to the square of the distance.

$I\alpha \frac{1}{r^{2} }$

Now according to the question the distance is increased by three times than,

$\frac{I_{2} }{I_{1} }=\frac{r_{1}^{2} }{r_{2}^{2} }$

Therefore,

$\frac{I_{2} }{I_{1} }=\frac{r_{1}^{2} }{(3r_{1})^{2} }\\\frac{I_{2} }{I_{1} }=\frac{1}{9} \\{I_{2}=\frac{1}{9}{I_{1} }$

Therefore the intensity will become 1/9 times to the initial intensity.

3 0

3 years ago

Directions: Complete the concept map using the terms listed below.

Komok [63]

Answer:

this is confusing

Explanation:

6 0

3 years ago

The position of a circuit breaker (CB) are .............

AlexFokin [52]

A circuit breaker is an automatically operated electrical switch designed to protect an electrical circuit from damage caused by excess current from an overload or short circuit. Its basic function is to interrupt current flow after a fault is detected.

I hope that this answer helps you

6 0

3 years ago