Answer:
<h2>
6.79</h2>
Step-by-step explanation:
According to Question,
![{x}^{2} = 46](https://tex.z-dn.net/?f=%20%7Bx%7D%5E%7B2%7D%20%20%3D%2046)
Squaring on both sides
![\sqrt{ {x}^{2} } = \sqrt{46}](https://tex.z-dn.net/?f=%20%5Csqrt%7B%20%7Bx%7D%5E%7B2%7D%20%7D%20%20%3D%20%20%5Csqrt%7B46%7D%20)
Calculate
![x = 6.79](https://tex.z-dn.net/?f=x%20%3D%206.79)
Let's check :
If we multiply 6.79 by itself, then the result will be approximately 46.
Hope this helps..
Best regards!!
Answer:
ummm where is the question anyway?
If it is 500 metres underwater when measured from a 40 degree angle, you can use trigonometry. 500 metres is the hypotenuse, and the angle from the submarine to the surface of water is 90. It is a right-angled triangle.
Using sin, where S = O/H, we have no opposite, only angles and a hypotenuse. So, sin 30 (the angle) = O/500. By multiplying each side by 500 to cancel O out, you get sin 30 x 500 = O.
So, The depth (from a 90 degree angle to the surface) = 294 metres.