3 years ago

What learning is required to become a mechanical engineer?

Engineering

1 answer:

Vinvika [58]3 years ago

3 0

bachelor's degree in mechanical engineering or mechanical engineering technology

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If OSHA determines that an employer's response to a non-formal complaint is adequate, what options does the employee filing the

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3 years ago

A geothermal pump is used to pump brine whose density is 1050 kg/m3 at a rate of 0.3 m3/s from a depth of 200 m. For a pump effi

nasty-shy [4]

Answer:

Input power of the geothermal power will be 686000 J

Explanation:

We have given density of brine $\rho =1050kg/m^3$

Rate at which brine is pumped $V=0.3m^3/sec$

So mass of the pumped per second

Mass = volume × density = $1050\times 0.3=315$ kg/sec

Acceleration due to gravity $g=9.8m/sec^2$

Depth h = 200 m

So work done $W=mgh=315\times 9.8\times 200=617400J$

Efficiency is given $\eta =0.9$

We have to fond the input power

So input power $=\frac{617400}{0.9}=686000J$

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3 years ago

If you measured a pressure difference of 50 mm of mercury across a pitot tube placed in a wind tunnel with 200 mm diameter, what

mart [117]

Answer:

V=33.66 m/s

$Re=448.8\times 10^6$

Re>4000, The flow is turbulent flow.

Explanation:

Given that

Pressure difference = 50 mm of Hg

We know that density of Hg=136000 $Kg/m^3$

ΔP= 13.6 x 1000 x 0.05 Pa

ΔP=680 Pa

Diameter of tunnel = 200 mm

Property of air at 25°C

ρ=1.2 $Kg/m^3$

Dynamic viscosity

$\mu =1.8\times 10^{-8}\ Pa.s$

Velocity of fluid given as

$V=\sqrt{\dfrac{2\Delta P}{\rho_{air}}}$

$V=\sqrt{\dfrac{2\times 680}{1.2}}$

V=33.66 m/s

Reynolds number

$Re=\dfrac{\rho _{air}Vd}{\mu }$

$Re=\dfrac{1.2\times 33.66\times 0.2}{1.8\times 10^{-8}}$

$Re=448.8\times 10^6$

Re>4000,So the flow is turbulent flow.

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3 years ago