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lisov135 [29]
3 years ago
15

Express the following in scientific notation 87025

Chemistry
1 answer:
uranmaximum [27]3 years ago
6 0

8.7025*10^4


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Witch wave is mad up of vibrating electric and magnetic fields that can move through space at the speed of light
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Answer:

Hiya! Your answer would be an Electromagnetic Wave.

Explanation:

Electromagnetic Wave is an electromagnetic wave that travels through space at the speed of light at about 300,000 kilometers per second. So when we talk about light traveling in waves, we can also talk about frequency, or the number of wavelengths that pass a certain point in a given length of time. We usually measure this as the number of wavelength cycles that pass per second. The units for this measurement are Hertz (hz).

So, if the wavelength of a light wave is shorter, that means that the frequency will be higher because one cycle can pass in a shorter amount of time. This means that more cycles can pass by the set point in 1 second. Likewise, a light wave that has a longer wavelength will have a lower frequency because each cycle takes a longer time to complete.

Hope I helped and I hope you get it right! :). Have a lovely day my friend!

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A Jaguar runs 4209 meters at the of 1400 meters per minute
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4 0
3 years ago
Silver (Ag) has two stable isotopes: 107Ag, 106.90 amu, and 109Ag, 108.90 amu. If the average atomic mass of silver is 107.87 am
inysia [295]

Answer:

  • The abundance of 107Ag is 51.5%.
  • The abundance of 109Ag is 48.5%.

Explanation:

The <em>average atomic mass</em> of silver can be expressed as:

107.87 = 106.90 * A1 + 108.90 * A2

Where A1 is the abundance of 107Ag and A2 of 109Ag.

Assuming those two isotopes are the only one stables, we can use the equation:

A1 + A2 = 1.0

So now we have a system of two equations with two unknowns, and what's left is algebra.

First we<u> use the second equation to express A1 in terms of A2</u>:

A1 = 1.0 - A2

We <u>replace A1 in the first equation</u>:

107.87 = 106.90 * A1 + 108.90 * A2

107.87 = 106.90 * (1.0-A2) + 108.90 * A2

107.87 = 106.90 - 106.90*A2 + 108.90*A2

107.87 = 106.90 + 2*A2

2*A2 = 0.97

A2 = 0.485

So the abundance of 109Ag is (0.485*100%) 48.5%.

We <u>use the value of A2 to calculate A1 in the second equation</u>:

A1 + A2 = 1.0

A1 + 0.485 = 1.0

A1 = 0.515

So the abundance of 107Ag is 51.5%.

3 0
3 years ago
Calculate the temperature in k of 3.05 moles of gas occupying 3.70 L at 4.12 atm
Gnoma [55]

Answer:

{ \bf{PV = nRT}} \\ { \tt{(4.12 \times 3700) = 3.05 \times 0.083 \times T }} \\ { \tt{15244 = 0.25315 \: T}} \\ { \tt{T = 6.02 \times  {10}^{4} \: kelvin }}

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3 years ago
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