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lana [24]
3 years ago
11

A 2.00-kg object is attached to a spring and placed on a frictionless, horizontal surface. A horizontal force of 20.0N is requir

ed to hold the object at rest when it is pulled 0.200m from its equilibrium position (the origin of the x axis). The object is now released from rest from this stretched position, and it subsequently undergoes simple harmonic oscillations. Find
(a) the force constant of the spring,
(b) the frequency of the oscillations, and
(c) the maximum speed of the object.
(d) Where does this maximum speed occur?
(e) Find the maximum acceleration of the object.
(f) Where does the maximum acceleration occur?
(g) Find the total energy of the oscillating system. Find
(h) the speed and
(I) acceleration of the object when its position is equal to one-third the maximum value (of its displacement).

Physics
1 answer:
dlinn [17]3 years ago
6 0

Answer: a. K=100N/m

b. F=1.22 Hz,. c. V=1.41m/s,. d. V is maximum at the mid point.

e. acceleration=9.91m/s²

f. At the ends where the restoring force is maximum

g. Total energy= 2J

h. Speed w = 7.04rad/s

I. Acceleration at one- third displacement= 6.6m/s²

Explanation: The procedures as been worked out clearly. I have attached it here. The questions are lenghty so it will be more convenient that way. Thanks for understanding.

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lawyer [7]

I SAID don’t copy from internet but u did

Explanation:

5 0
3 years ago
An a.c. supply is connected to a wire stretched between the poles of a magnet. Which way does the wire move?​
snow_lady [41]
The wire vibrates back and forth between the poles of the magnet.
The frequency of the vibration is the frequency of the AC supply.

7 0
2 years ago
A particle with mass 1.81*10^-3kg and a charge of 1.22*10^-8C has, at a given instant, a velocity v= (3.0*10^4 m/s)j.
charle [14.2K]

Answer:

a = -0.33 m/s² k^

Direction: negative

Explanation:

From Newton's law of motion, we know that;

F = ma

Now, from magnetic fields, we know that;. F = qVB

Thus;

ma = qVB

Where;

m is mass

a is acceleration

q is charge

V is velocity

B is magnetic field

We are given;

m = 1.81 × 10^(−3) kg

q = 1.22 × 10 ^(−8) C

V = (3.00 × 10⁴ m/s) ȷ^.

B = (1.63T) ı^ + (0.980T) ȷ^

Thus, since we are looking for acceleration, from, ma = qVB; let's make a the subject;

a = qVB/m

a = [(1.22 × 10 ^(−8)) × (3.00 × 10⁴)ȷ^ × ((1.63T) ı^ + (0.980T) ȷ^)]/(1.81 × 10^(−3))

From vector multiplication, ȷ^ × ȷ^ = 0 and ȷ^ × i^ = -k^

Thus;

a = -0.33 m/s² k^

7 0
3 years ago
Suzanne notices that when sunlight strikes the surface of a calm lake, it creates a glare. Which statement accurately describes
kumpel [21]
<span>The answer is C. This is called polarization of light by reflection. The sunlight is reflected at a parallel angle from on the surface plane of the water from which it bounces from. The glare is due to this polarization of sun beams at an angle with respect to the viewer. </span>




4 0
3 years ago
What do the arrows in food chains represent
OLga [1]
To represent in order how the animals

6 0
4 years ago
Read 2 more answers
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