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lana [24]
3 years ago
11

A 2.00-kg object is attached to a spring and placed on a frictionless, horizontal surface. A horizontal force of 20.0N is requir

ed to hold the object at rest when it is pulled 0.200m from its equilibrium position (the origin of the x axis). The object is now released from rest from this stretched position, and it subsequently undergoes simple harmonic oscillations. Find
(a) the force constant of the spring,
(b) the frequency of the oscillations, and
(c) the maximum speed of the object.
(d) Where does this maximum speed occur?
(e) Find the maximum acceleration of the object.
(f) Where does the maximum acceleration occur?
(g) Find the total energy of the oscillating system. Find
(h) the speed and
(I) acceleration of the object when its position is equal to one-third the maximum value (of its displacement).

Physics
1 answer:
dlinn [17]3 years ago
6 0

Answer: a. K=100N/m

b. F=1.22 Hz,. c. V=1.41m/s,. d. V is maximum at the mid point.

e. acceleration=9.91m/s²

f. At the ends where the restoring force is maximum

g. Total energy= 2J

h. Speed w = 7.04rad/s

I. Acceleration at one- third displacement= 6.6m/s²

Explanation: The procedures as been worked out clearly. I have attached it here. The questions are lenghty so it will be more convenient that way. Thanks for understanding.

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A student makes a simple pendulum by attaching a mass to the free end of a 1.50-meter length of string suspended from the ceilin
Fofino [41]

Answer:

The mass has likely lost some of its mechanical energy to resistance on its path.

Explanation:

The mechanical energy of an object is the sum of its kinetic and potential energies (KE and PE.) Ideally, the mechanical energy of a simply pendulum should be "conserved." In other words, the sum of the kinetic and potential energy of the simply pendulum should stays the same as it travels along its path.

Indeed, as the pendulum travels, some of its PE will convert to KE and back. However, the sum of these two energies is supposed to stay the same.

  • When the pendulum moves from the highest point to the bottom of the path, some of its PE converts to KE. (The pendulum speeds up in this process.)
  • When the pendulum moves from the bottom of its path to the opposite side, its KE is converted back to PE. (The pendulum slows down as it moves towards the other side of the path.)

However, in practice, the mechanical energy of pendulums isn't always conserved. For example, various kinds of resistances (such as air resistance) act on the pendulum as it moves. That would slow down the pendulum. Some of the pendulum's energies would be converted to heat and is lost to the surroundings.

In effect, the mechanical energy of the pendulum would become smaller and smaller over time. When the pendulum travels back towards the girl, its potential energy would be smaller than the initial value when at the girl's chin.

5 0
3 years ago
The flow of electrons from one atom to another is called
lara31 [8.8K]

Electron Cloud and nuclei


8 0
3 years ago
Calculate the gravitational potential energy of the interacting pair of the Earth and a 11 kg block sitting on the surface of th
trasher [3.6K]

Answer:

Gravitational potential energy (GPE) = 107.8J

Explanation:

Gravitational potential energy (GPE) = mgh

Where mass(m) = 11kg

Acceleration due to gravity(g) = 9.8m²/s

height = assumed to be 1m

Force(F) = mg

Force(F) = 11×9.8 = 107.8N

Gravitational potential energy (GPE) = 107.8×1

= 107.8J

5 0
3 years ago
A camcorder has a power rating of 13 watts. If the output voltage from its battery is 6 volts, what current does it use?
leva [86]

Power = (voltage) x (current)

13 watts = (6 volts) x (current)

Divide each side by (6 volts):

Current = (13 watts) / (6 volts)

Current = (13/6) Amperes

<em>Current = 2.17 Amperes</em>

5 0
4 years ago
A truck driver is broadcasting at a frequency of 27.075 MHz with a CB (citizen's band) radio. Determine the wavelength of the el
Sergio [31]

Answer:

11m

Explanation:

Wavelength of a wave is the distance between successive crests and trough of a wave. It is represented mathematically as the ratio of the speed of the wave to its frequency. It can be expressed as;

Wavelength ¶ = wave speed (v) /frequency (f)

Given the speed of light c = 2.9979 10^8 m/s.

frequency of the radio wave = 27.075 MHz = 27.075×10^6Hz

Wavelength = 2.9979 10^8/27.075×10^6

Wavelength = 0.11×10^2

Wavelength = 11m

Therefore, the wavelength of the electromagnetic wave being used is 11m

3 0
3 years ago
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