Record observations, pose a question, create a test for an individual variable, test, come to a conclusion
Answer:
-125.4
Explanation:
Target equation is 4C(s) + 5H2(g) = C4H10
These are the data equations for enthalpy of combustion
- C(s) + O2(g) =O2(g) -393.5 kJ/mol * 4
- H2(g) + ½O2(g) =H20(l) = 285.8 kJ/mol * 5
- 2CO2(g) + 3H2O(l) = 13/2O2 (g) + C4H10 - 2877.1 reverse
To get target equation multiply data equation 1 by 4; multiply equation 2 by 5; and reverse equation 3, so...
Calculate 4(-393.5) + 5(-285.8) + 2877.6 and you should get the answer.
Answer:
453.592 grams
Explanation:
Given
Mass = 1 lb
Required.
Convert to grams using dimensional analysis
Represent 1 lb with x g
In unit conversion, we have that.
1 lb = 453.592 g
So:
Getting the equivalent of lb in g, we have:
x g = 1 lb * (453.592 g/ 1 lb)
x g = 1 * 453.592 g
x g = 453.592 grams
Hence:
The equivalent of 1 lb in grams is 453.592 grams
