Continent
jig-saw shapes when puzzled and combined together, formed one big continent -
Pangea, and was separated by drifts.
Fossil
comparisons of different species were discovered into two different, separated
continents in which when you combine them, they were one in the past.
Seismic,
volcanic, and geothermal activity are found along imagined plate
boundaries.
Plates
were actually rubbing against each other as evidence is seen on the formed
mountain ranges.
<span>
Paleomagnetism,
magnetic field placement in the layers of the rock are present.</span>
Answer:
Le calcul du courant se fait avec deux éléments : la tension et la valeur de la résistance. Courant (A) = tension (V) / résistance (Ohm) ce qui donne la formule I = U/R.
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Answer:
The magnitude of the horizontal net force is 13244 N.
Explanation:
Given that,
Mass of car = 1400 kg
Speed = 17.7 m/s
Distance = 33.1 m
We need to calculate the acceleration
Using equation of motion
Where, u = initial velocity
v = final velocity
s = distance
Put the value in the equation
Negative sign shows the deceleration.
We need to calculate the net force
Using newton's formula
Negative sign shows the force is opposite the direction of the motion.
The magnitude of the force is
Hence, The magnitude of the horizontal net force is 13244 N.
Answer:
Explanation:
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Answer:
a) x = 4.33 m
, b) w = 2 rad / s
, f = 0.318 Hz
, c) a = - 17.31 cm / s²,
d) T = 3.15 s, e) A = 5.0 cm
Explanation:
In this exercise on simple harmonic motion we are given the expression for motion
x = 5 cos (2t + π / 6)
they ask us for t = 0
a) the position of the particle
x = 5 cos (π / 6)
x = 4.33 m
remember angles are in radians
b) The general form of the equation is
x = A cos (w t + Ф)
when comparing the two equations
w = 2 rad / s
angular velocity and frequency are related
w = 2π f
f = w / 2π
f = 2 / 2pi
f = 0.318 Hz
c) the acceleration is defined by
a == d²x / dt²
a = - A w² cos (wt + Ф)
for t = 0
, we substitute
a = - 5,0 2² cos (π / 6)
a = - 17.31 cm / s²
d) El period is
T = 1/f
T= 1/0.318
T = 3.15 s
e) the amplitude
A = 5.0 cm
