Answer:
Mass = 357.7 g
Explanation:
Given data:
Mass of Fe = 250 g
Mass of oxygen = 120 g
Mass of iron(III) oxide produced = ?
Solution:
Chemical equation:
4Fe + 3O₂ → 2Fe₂O₃
Number of moles of Fe:
Number of moles = mass/molar mass
Number of moles = 250 g/ 55.8 g/mol
Number of moles = 4.48 mol
Number of moles of O₂ :
Number of moles = mass/molar mass
Number of moles = 120 g/ 32 g/mol
Number of moles = 3.75 mol
Now we will compare the moles of reactants with product.
Fe : Fe₂O₃
4 : 2
4.48 : 2/4×4.48 = 2.24
O₂ : Fe₂O₃
3 : 2
3.75 : 2/3×3.75= 2.5
Less number of moles of Fe₂O₃ are produced by Fe thus it will act as limiting reactant.
Mass of Fe₂O₃:
Mass = number of moles × molar mass
Mass = 2.24 mol × 159.69 g/mol
Mass = 357.7 g
Explanation:
atomic mass
Really...i think it can also be atomic number..
The correct term for each statement is as follows;
- Caves being formed by acid rain dissolving underground limestone - weathering
- Deltas forming at the mouths of rivers - deposition
- Glaciers scraping rocks across the earth’s surface - erosion
- Rocks being made smooth by tumbling across a stream bed - weathering
- Ponds filling up with sediment and becoming marshes - deposition
<h3>What is weathering?</h3>
Weathering in geology is the mechanical or chemical breaking down of rocks in situ by weather or other causes. options 7 and 14 are the case in this scenario as there is a breakdown of limestone and rocks.
Erosion is the result of having been worn away or eroded, as by a glacier on rock or the sea on a cliff face. Agents of erosion are water, ice or wind. Options 12 is an example of erosion because glaciers are wearing off rocks.
Deposition is the laying down of sediment carried by wind, flowing water, the sea or ice. Sediment can be transported as pebbles, sand and mud, or as salts dissolved in water. Options 8 and 15 are examples of deposition.
Learn more about weathering and deposition at: brainly.com/question/367069
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Answer:
K
Explanation:
Since the blood moves from the body to the right atrium to the right ventricle
The volume of HCl required is 23.89 mL
Calculation of volume:
The reaction:
As HCl and NaOH react in 1 : 1 ratio.
Volume of NaOH= 718 mL
Concentration= 0.183M
Volume of HCl= ?
Concentration= 5.50M
Using the dilution formula:
Therefore,
Volume of HCl required will be 23.89 mL.
Learn more about neutralization reaction here,
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