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3 years ago

What do acids and bases have in common apex?

2 answers:

8 0

Both acids and bases produce a part of a water molecule. Bases dissociate hydroxide (–OH) ions and acids, hydrogen (H+) ions that when combined form water. Both are also very corrosive when they are strong enough that they fully dissociate in water.

tiny-mole [99]3 years ago

7 0

Explanation:

Acids are the substances that have pH less than 7. They are acidic in nature and have a sour taste.

Acids give hydrogen ions ( $H^{+}$ ) upon dissociation in water.

On the other hand, bases are the substances that have pH more than 7. They are basic in nature and have bitter taste.

Bases dissociate in water to give hydroxide ions ( $OH^{-}$ ).

Since, both acids and bases dissociate to give ions. Hence, we can conclude that both acids and bases are able to conduct electricity.

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Consider the following equilibrium:

Ainat [17]

<u>Answer: </u>The equation which is wrong is $K_p=K_c(RT)^{-5}$

<u>Explanation:</u>

For the given reaction:

$4Fe(s)+3O_2(g)\rightarrow 2Fe_2O_3(s)$

The expression for $K_c\text{ and }K_p$ is given by:

$K_c=\frac{1}{[O_2]^3}$

$K_p=\frac{1}{[O_2]^3}$

The concentration of solids are taken to be 1, only concentration of gases and liquid states are taken. The pressure of only gases are taken.

Relationship between $K_p\text{ and }K_c$ is given by the expression:

$K_p=K_c\times (RT)^{\Delta n_g}$

where,

$\Delta n_g$ = number of moles of gaseous products - number of moles of gaseous reactants

R = gas constant

T= temperature

For the above reaction,

$\Delta n_g$ = number of moles of gaseous products - number of moles of gaseous reactants = 0 - 3 = -3

Hence, the expression for $K_p$ is:

$K_p=K_c\times (RT)^{-3}$

Therefore, the equation which is wrong is $K_p=K_c(RT)^{-5}$

7 0

3 years ago

For a different reaction, the plot of the reciprocal of concentration versus time in seconds was linear with a slope of 0.056 M-

Bond [772]

Answer:

$C_t=0.165M$

Explanation:

From the question we are told that:

Slope $K=0.056 M-1 s -1$

initial Concentration $C_1=2.2M$

Time $t=100$

Generally the equation for Raw law is mathematically given by

$\frac{1}{C}_t=kt+\frac{1}{C}_0$

$\frac{1}{C}_t=0.056*100+\frac{1}{2.2}_0$

$C_t=0.165M$

4 0

3 years ago

When an electron moves from a lower energy level to a higher energy level, the atom:

Ede4ka [16]

Answer:

A. absorbs light

Explanation:

For an electron to move from a lower energy level to a higher energy level, energy needs to be added to the atom.

In most cases this required energy will be light: The electron of the atom will absorb the energy of the light and move to a higher energy level.

When said electron comes back to the lower energy level, the atom will conversely give off light.

5 0

2 years ago

Tema: Métodos de Separação de Misturas – Homogêneas e Heterogêneas;

seraphim [82]

Answer:

fjskeowkcnekvo Dee five votes come vote for dog even r

4 0

2 years ago

How many moles of KBr are present in 500 ml of a 0.8 M KBr solution?

faltersainse [42]

Answer:

2) 0.4 mol

Explanation:

Step 1: Given data

Volume of the solution (V): 500 mL

Molar concentration of the solution (M): 0.8 M = 0.8 mol/L

Step 2: Convert "V" to L

We will use the conversion factor 1 L = 1000 mL.

500 mL × 1 L/1000 mL = 0.500 L

Step 3: Calculate the moles of KBr (solute)

The molarity is the quotient between the moles of solute (n) and the liters of solution.

M = n/V

n = M × V

n = 0.8 mol/L × 0.500 L = 0.4 mol

4 0

2 years ago