KE = 1/2 * m* v^2
= 1/2 * 40 * 225
= 4500 J
hope it helped
Answer:
Explanation:
ω =
k = 2.5 N/m
m = 10 kg
ω = .5 rad /s
x(t) = A cos(ωt + φ₀)
When t = 0 , x(t) = 0
0 = A cos(ωx 0 + φ₀)
cos φ₀ = 0
φ₀ = π /2
x(t) = A cos(ωt +π /2 )
Putting the value of ω
x(t) = A cos(.5 t +π /2 )
Differentiating on both sides
dx(t)/dt = - .5 A sin(.5 t +π /2 )
v(t) = - .5 A sin(.5 t +π /2 )
Given t =0 , v(t) = -5 m/s
-5 = - .5 A sin(.5 x0 +π /2 )
-5 = - .5 A sinπ /2
A = 10 m
x(t) = 10 cos( .5 t +π /2 )
b )
when t = π ( 3.14 s )
x(t) = - 10 m
when t = 2π ( 6.28s )
x(t) = 0
when t = 3π ( 9.42 s )
x(t) = 10 m
and so on
Answer:
20 Joules
Explanation:
Mechanical Energy is the sum of kinetic and potential energy.
Since energy can only be transferred and cannot be lost, kinetic energy=potential energy.
Now we only need to use one of the formulas to find the answer. In this answer I'll be using the formula for potential energy which is mass × gravitational field strength ×height.
Substitute the values in and using gfs=10, the answer will be 20J.
As the radius increases the circumference increases.
12 cm x 2 cm x 3 cm = 72 cm3