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kondor19780726 [428]
3 years ago
14

Hashim, a 69-year-old, makes errors while performing tasks. He is unable to detect and correct the errors. He is also unable to

deal effectively with difficult or novel circumstances. Given this information, it can be said that:
Physics
1 answer:
zavuch27 [327]3 years ago
3 0

Question:

The options are;

A. Hashim's selective attention has increased.

B. Hashim's brain receives increased supplies of blood.

C. Hashim has deficiencies in executive attention.

D. Hashim has high blood pressure.

Answer:

The correct option is;

C. Hashim has deficiencies in executive attention.

Explanation:

Executive attention is the brain function that permits the setting of priorities of relevant observations from irrelevant observations, such that competing attention requiring observations can be resolved. The process of executive attention can be shown in mental exercises where the subject, based on his will, tries to redirect observed sensation, by making more important non-emotional features.

Executive attention enables the brain to focus and to isolate events thereby aiding in problem solving.

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Identify the following items as scalar or vector.
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An electric generator transforms mechanical energy into electrical energy. This process could be done by which of these?
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A ball rolls down the hill which has a vertical height of 15 m. Ignoring friction what would be the gravitational potential ener
trasher [3.6K]

a) Potential energy: 147 m [J]

The gravitational potential energy of an object is given by

U=mgh

where

m is its mass

g=9.8 m/s^2 is the acceleration of gravity

h is the height of the object above the ground

In this problem,

h = 15 m

We call 'm' the mass of the ball, since we don't know it

So, the potential energy of the ball at the top of the hill is

U=(m)(9.8)(15)=147 m (J)

b) Velocity of the ball at the bottom of the hill: 17.1 m/s

According to the law of conservation of energy, in absence of friction all the potential energy of the ball is converted into kinetic energy as the ball reaches the bottom of the hill. Therefore we can write:

U=K=\frac{1}{2}mv^2

where

v is the final velocity of the ball

We know from part a) that

U = 147 m

Substituting into the equation above,

147 m = \frac{1}{2}mv^2

And re-arranging for v, we find the velocity:

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