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krok68 [10]
3 years ago
7

What are two chemical properties of chromium? Please?

Chemistry
2 answers:
melomori [17]3 years ago
8 0

Chromium is a fairly active metal. It does not react with water, but reacts with most acids. It combines with oxygen at room temperature to form chromium oxide (Cr 2 O 3 ). Chromium oxide forms a thin layer on the surface of the metal, protecting it from further corrosion (rusting).  


noname [10]3 years ago
7 0
It's brittle and hard..........
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When solving a problem it is important to identify your given and needed units, but it is also important to understand the relat
Angelina_Jolie [31]

Answer:

The question has some details missing. here are the details ; Given the following ;  

1. 43.2 g of tablet with 20 cm3 of space

2. 5 cm3 of tablets weighs 10.8 g

3. 5 g of balsa wood with density 0.16 g/cm3

4. 150 g of iron. With density 79g/cm 3

5. 32 cm3 sample of gold with density 19.3 g/cm3

6. 18 ml of cooking oil with density 0.92 g/ml

Explanation:

<u>Appropriate for calculating mass</u>

32 cm3 sample of gold with density 19.3 g/cm3

18 ml of cooking oil with density 0.92 g/ml

<u>Appropriate for calculating volume</u>

5 g of balsa wood with density 0.16 g/cm3

150 g of iron. With density 79g/cm 3

<u>Appropriate for calculating density</u>

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5 cm3 of tablets weighs 10.8 g

3 0
3 years ago
explain how a metal with one valence electron compares with a metal with more than one valence electron
slamgirl [31]

Explanation:

A metal with one valence electron is highly reactive compared to those with more than one electron.

Atoms including those of metals reacts in order attain a stable electronic configuration just like those of noble gases.

An atom with one valence electron have just one electron in its valence shell.

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learn more:

Valence electrons brainly.com/question/3023499

#learnwithBrainly

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6 0
3 years ago
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If 28 ml of 5.8 m h2so4 was spilled, what is the minimum mass of nahco3 that must be added to the spill to neutralize the acid?
ipn [44]

First we have to refer to the reaction between the acid and the base: <span>

H2SO4 + 2 NaHCO3 ---> 2 H2O + 2 CO2 + Na2SO4 

From this balanced equation we can see that for every 1 mol of acid (H2SO4), we need 2 mol of base (NaHCO3) to neutralize it. Given 28 ml of 5.8 M acid, we need to find out how many mols of acid that is: 

<span>28mL * (1L/1000mL) * 5.8 mol/L =  0.1624 mol H2SO4</span></span>

<span>
Since we need 2 mol of base per mol of acid, we need:</span>

<span> 2*0.1624 mol = 0.3248 mol NaHCO3 </span><span>

MolarMass of NaHCO3 is 84.01 g/mol 

<span>0.3248 mol*(84.01g/mol) = 27.29 g NaHCO3</span></span>

3 0
2 years ago
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