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2 years ago

6

The quantitative amount of charge separation in a diatomic molecule contributes to the dipole moment of that molecule. A. True B

. False

1 answer:

SOVA2 [1]2 years ago

8 0

Answer:

The answer is True.

Explanation:

The sentence above is true it all adds up.

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when the volume of a gas is changed from 3.75 L to 6.52 L the temperature will change from 100k to blank k

Makovka662 [10]

Guy-Lussac's Law states that the volume and the temperature are directly proportional given that the pressure remains constant.

For this problem, we will assume constant pressure. Based on the law:
(Volume/Temperatur)1 = (Volume/Temperature)2
(3.75/100) = (6.52/T)
T = 166.667 kelvin

4 0

3 years ago

Read 2 more answers

Iodine and strontium are reacted together. explain why it is more difficult to predict whether this reaction is more or less rea

Juli2301 [7.4K]

<u>Answer: </u>The reaction between iodine and strontium is less reactive than the reaction of bromine and strontium.

<u>Explanation:</u>

Iodine and bromine belong to the same group which is Group 17 of the periodic table. Iodine lies in Period 5 and bromine lies in Period 4.

Reactivity of non-metals is defined as the tendency of the elements to gain electrons easily. This depends on the electronegativity values. More the electronegativity, more will be the reactivity and vice-versa.

Reactivity of non-metals decreases from moving down the group and increases across the period.

The electronegativity of iodine is less than bromine. Hence, it is less reactive than the bromine.

The reaction between strontium and bromine is more favorable because it is the reaction between two reactive elements.

Hence, the reaction between iodine and strontium is less reactive than the reaction of bromine and strontium.

8 0

3 years ago

Ionization energy is g higher for potassium than lithium.<br> a. True<br> b. False

MArishka [77]

Answer:

fasle

Explanation:

best the door cjjr

3 0

3 years ago

Calculate the number of moles of NaCl contained in .5000 L of a 1.5 M (Molarity) solution.

mote1985 [20]

Answer:

The number of moles of NaCl contained in 0.5000 L of a 1.5 M (Molarity) solution is 0.75 moles.

Explanation:

Molar concentration is a measure of the concentration of a solute in a solution, be it some molecular, ionic, or atomic species.

Molarity M is the number of moles of solute that are dissolved in a given volume.

The Molarity of a solution is determined by the following expression:

$Molarity=\frac{number of moles of solute}{volume}$

Molarity is expressed in units $\frac{moles}{liter}$ .

In this case:

Molarity= 1.5 M
number of moles of solute= ?
volume= 0.5 L

Reemplacing:

$1.5 M=\frac{number of moles of solute}{0.5 L}$

Solving:

number of moles of solute= 1.5 M* 0.5 L

number of moles of solute= 0.75

<u><em>The number of moles of NaCl contained in 0.5000 L of a 1.5 M (Molarity) solution is 0.75 moles.</em></u>

5 0

3 years ago

Use the reaction below for the decomposition of sodium azide

bezimeni [28]

<u>Answer:</u> The volume of nitrogen gas at STP is 44.8 L.

<u>Explanation:</u>

The number of moles is defined as the ratio of the mass of a substance to its molar mass. The equation for it follows:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ ...(1)

We are given:

Given mass of $NaN_3$ = 130.0 g

Molar mass of $NaN_3$ = 65.01 g/mol

Using equation 1:

$Moles of NaN_3=\frac{130.0 g}{65.01g/mol}=2mol$

For the given chemical equation:

$2NaN_3(s) \rightarrow 2Na(s) + 3N_2(g)$

By the stoichiometry of the reaction:

2 moles of $NaN_3$ produces 3 moles of nitrogen gas

At STP:

1 mole of a gas occupies 22.4 L of volume

So, 2 moles of nitrogen gas will occupy $=\frac{22.4L}{1mol}\times 2mol=44.8L$ of volume

Hence, the volume of nitrogen gas at STP is 44.8 L.

8 0

3 years ago