Answer:
CuSO₄(aq) + 2 KF(aq) = CuF₂ + K₂SO₄
Explanation:
<em>The question is missing but I think it must be about writing and balancing the equation.</em>
Let's consider the unbalanced equation for the reaction that occurs when aqueous copper (II) sulfate reacts with aqueous potassium fluoride to produce a precipitate of copper (II) fluoride (<em>I fixed a mistake here</em>) and aqueous potassium sulfate. This is a double displacement reaction.
CuSO₄(aq) + KF(aq) = CuF₂ + K₂SO₄
Since only K and F atoms are not balanced, we will get the balanced equation by multiplying KF by 2.
CuSO₄(aq) + 2 KF(aq) = CuF₂ + K₂SO₄
Answer:
Mitosis meiosis
Explain:
Mitosis is where the cell splits into 2 more cells (diploid)
Meiosis is where the cell splits into 2, and then split again, making 4 (haploid)
ΔH = -15.78 KJ when 25.0 g of S₈ reacts.
<h3>What is Balanced Chemical Equation ?</h3>
The balanced chemical equation is the equation in which the number of atoms on the reactant side is equal to the number of atoms on the product side in an equation.
The given reaction balanced equation is:
1/8 S₈(s) + H₂(g) → H₂S(g) ΔH = -20.22kj
Now,
When 1 mol will react, then ΔH = -20.2 × 8
= -161.6 KJ
When 1 mol of S8 = 8 × 32 g
= 256 g
When 256g of S8 react ΔH = -161.6 KJ
When 1 g reacts, ΔH =
=- 0.63125 KJ
When 25 g reacts, ΔH = - 0.63125 × 25
= -15.78 KJ
Thus from the above conclusion we can say that ΔH = -15.78 KJ when 25.0 g of S₈ reacts.
Learn more about the Balanced chemical equation here: brainly.com/question/26694427
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Explanation:
A stable isotope is one that does not emit radiation, or, if it does its half-life is too long to have been measured. It is believed that the stability of the nucleus of an isotope is determined by the ratio of neutrons to protons.
Hope this helps you out : D